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Vladimir [108]
3 years ago
7

A shark swims around his circular pool. What is the centripetal force of the 681kg shark if the pool has a diameter of 14m and i

t is swimming 1 lap in 80s
Physics
1 answer:
blsea [12.9K]3 years ago
5 0
<span>29 Newtons
   Centripetal force is modeled by the equation:
  F = MV^2/R where
 F = force
 M = Mass
 V = Velocity
 R = Radius

   I will assume the shark is swimming in a circle with a radius of 14 m / 2 = 7 m. The actual radius will be smaller, but I'll assume that the question is simply poorly worded. So we need to calculate the velocity of the shark. The circumference of the circle is pi*14m = 43.98229715 m. And since velocity is defined as distance over time, we have a velocity of 43.98229715 m / 80 s = 0.549778714 m/s.

   Now substitute the known values into the equation for centripetal force.
 F = MV^2/R
 F = 681 kg * ( 0.549778714 m/s)^2 / 7m
 F = 681 kg * 0.302256635 m^2/s^2 / 7m
 F = 205.8367683 kg*m^2/s^2 / 7m
 F = 29.40525261 kg*m/s^2
 F = 29.40525261 N
   Rounding to 2 significant figures gives a force of 29 Newtons.</span>
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satela [25.4K]

Answer:

The correct answer is V√5

Explanation:

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Let V(5r) be the velocity of the satellite orbiting at radius 5r.

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Where V is the escape velocity

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With the above equation, we can obtain the answer to the question as follow:

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Next, we'll obtained the ratio of V(5r) to V as shown below

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To solve this problem we will apply the concepts related to the Impulse which can be defined as the product between mass and the total change in velocity. That is to say

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