Question

A 1.50 L sample of neon gas at 1.10 atm and 25 °C is heated to 45 °C. The neon gas is then subjected to a pressure of 1.50 atm. Determine the new volume of the neon gas

Answer 1

Answer:

1.17 L

Explanation:

Step 1: Given data

• Initial volume (V₁): 1.50 L

• Initial pressure (P₁): 1.10 atm

• Initial temperature (T₁): 25 °C

• Final volume (V₂): ?

• Final pressure (P₂): 1.50 atm

• Final temperature (T₂): 45 °C

Step 2: Convert the temperatures to the Kelvin scale

We will use the following expression.

K = °C + 273.15

K = 25°C + 273.15 = 298 K

K = 45°C + 273.15 = 318 K

Step 3: Calculate the final volume of the neon gas

If we assume ideal behavior, we can calculate the final volume of the neon gas using the combined gas law.

P₁ × V₁ / T₁ = P₂ × V₂ / T₂

V₂ = P₁ × V₁ × T₂ / T₁ × P₂

V₂ = 1.10 atm × 1.50 L × 318 K / 298 K × 1.50 atm = 1.17 L