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8090 [49]
2 years ago
5

H e l p m e p l e a s e

Mathematics
2 answers:
Alik [6]2 years ago
6 0

Answer:

The closest answer would be C

Step-by-step explanation:

this is split in 1/4th meaning what is 306.63 divided by 1/4?

Molodets [167]2 years ago
5 0

Answer:

D

Step-by-step explanation:

maybe this will help you .

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Maksim231197 [3]

Answer:

36?

Step-by-step explanation:

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Please help will give brainlist!​
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Answer:

b=\frac{1}{6}

Step-by-step explanation:

In f(x)=a\cos(b(x-c))+d, b represents a constant related to the period of the function. Here's how it's related:

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We're given T=12\pi, so solving for b:

b=\frac{2\pi}{12\pi}=\boxed{\frac{1}{6}}

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Bill weights 120 pounds and is gaining 10 pounds each month. Phil weights 150 pounds and is gaining 4 pounds each month. How man
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The answer should be 3 months

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If nx10^p is a positive number written in scientific notation which statements must be true? Select all that apply
liq [111]

For this case we have the following number written in scientific notation:


n * 10 ^ p

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Therefore, the following statements are true:

p ∈ (-∞, ∞)

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n ∈ [1, 10]

Answer:

The following statements are correct about the number written in scientific notation:

p ∈ (-∞, ∞)

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3 years ago
The Ohio Department of Agriculture tested 203 fuel samples across the state
Rus_ich [418]

Answer:

\hat p = \frac{14}{105}= 0.133

And that represent the proportion of failures.

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.133 - 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.0475

0.133 + 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.2185

The 99% confidence interval would be given by (0.0475;0.2185)

Step-by-step explanation:

Previous concept

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The proportion estimated would be:

\hat p = \frac{14}{105}= 0.133

And that represent the proportion of failures.

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.133 - 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.0475

0.133 + 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.2185

The 99% confidence interval would be given by (0.0475;0.2185)

3 0
3 years ago
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