13. Examine the following table, each letter represents a piece of missing information. Below

oils will dissolve best in solvents that are? A. polar B. nonpolar C. either polar or nonpolar D. neither polar nor nonpolar

Genrish500 [490]

The answer is <span>B. nonpolar.

Polar molecules dissolve best in polar solvents while nonpolar molecules dissolve best in nonpolar solvents. </span>Oils are nonpolar. So, they will dissolve best in nonpolar solvents. If you put oil in some polar solvent, such as water, it will hardly dissolve.

4 0

3 years ago

Which of the following factors drives all the weather on Earth, including large-scale storms and local weather systems? The ocea

katovenus [111]

The sun heats up the air at different rates. Weather is caused by uneven heating

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3 years ago

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CO(g)+2H2(g)⇌CH3OH(g)CO(g)+2H2(g)⇌CH3OH(g) This reaction is carried out at a different temperature with initial concentrations o

Katarina [22]

Answer:

9.4

Explanation:

The equation for the reaction can be represented as:

$CO_{(g)}$ + $2H_2O_{(g)}$ ⇄ $CH_3OH_{(g)}$

The ICE table can be represented as:

$CO_{(g)}$ + $2H_2_{(g)}$ ⇄ $CH_3OH_{(g)}$

Initial 0.27 0.49 0.0

Change -x -2x x

Equilibrium 0.27 - x 0.49 -2x x

We can now say that the concentration of $CH_3OH_{(g)}$ at equilibrium is x;

Let's not forget that at equilibrium $CH_3OH_{(g)}$ = 0.11 M

So:

x = [ $CH_3OH_{(g)}$ ] = 0.11 M

[ $CO_{(g)}$ ] = 0.27 - x

[ $CO_{(g)}$ ] = 0.27 - 0.11

[ $CO_{(g)}$ ] = 0.16 M

[ $2H_2_{(g)}$ ] = (0.49 - 2x)

[ $2H_2_{(g)}$ ] = (0.49 - 2(0.11))

[ $2H_2_{(g)}$ ] = 0.49 - 0.22

[ $2H_2_{(g)}$ ] = 0.27 M

$K_C = \frac{[CH_3OH]}{[CO][H_2]^2}$

$K_C = \frac{(0.11)}{(0.16)[(0.27)^2}$

$K_C = 9.4307$

$K_C$ = 9.4

∴ The equilibrium constant at that temperature = 9.4

8 0

3 years ago

The ______ force is equal to the weight of the fluid displaced by an object. gravitational friction buoyant

Tju [1.3M]

Buoyant

Buoyancy is the ability to float in fluids.
Gravity is the force of all objects attracted to one.
Friction is the force caused when two objects rub against each other causing them to slow

<span>Archimedes principle explains that the magnitude of that force is proportional to the difference in the pressure between the top and the bottom of the column, and</span> is also equivalent to the weight of the fluid that would otherwise occupy the column, i.e. the displaced fluid.

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Alcohols, carboxylic acids and water exhibit a very broad o—h peak between 3200-2600 cm-1. broad peaks are typically associated

kramer

Association Effects in Alcohols:

A broad peak is found in the IR spectrum of Alcohols in the range of 3500 cm⁻¹. The broadness is mainly due to special class of association effect called as hydrogen bonding. Hydrogen bonding mainly occur between the most electronegative element (F, O or N) of one molecule and the the hydrogen atom (attached to most electronegative atom) of another molecule.

Association Effects in Carboxylic Acids:

In carboxylic acids the -COOH group is responsible for the broadness of peak in IR spectrum at around 2600-3400 cm⁻¹. This broadness again results from the association effects called as dimerization in which a dimer of carboxylic acid is formed.

Association effect in Water:

The association effect found in water is also due hydrogen bond interactions as that found in case of Alcohols.

6 0

3 years ago