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skelet666 [1.2K]
3 years ago
13

A mineral is a naturally occurring solid with a regular, repeating structure. Please select the best answer from the choices pro

vided T F
Chemistry
2 answers:
ziro4ka [17]3 years ago
8 0

Answer: True,a mineral is a naturally occurring solid with a regular, repeating structure.

Explanation:

Minerals are natural occurring inorganic solid substance with fixed chemical composition. These solids are formed by repeating unit of their single crystal structure that is atom present in the minerals are arranged or placed in systematic pattern or fashion. For example : Halite is a mineral composed of  chlorine and sodium atoms arranged in a cubic pattern.

So, the given statement is true.

Natasha_Volkova [10]3 years ago
3 0
According to American Science Heritage Dictionary, it is true that a mineral is a naturally occurring solid with a regular, repeating structure.
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A 0.1510 gram sample of a hydrocarbon produces 0.5008 gram CO2 and 0.1282 gram H2O in combustion analysis. Its
Over [174]
In a combustion of a hydrocarbon compound, 2 reactions are happening per element:

C + O₂ → CO₂
2 H + 1/2 O₂ → H₂O

Thus, we can determine the amount of C and H from the masses of CO₂ and H₂O produced, respectively.

1.) Compute for the amount of C in the compound. The data you need to know are the following:
Molar mass of C = 12 g/mol
Molar mass of CO₂ = 44 g/mol
Solution:
0.5008 g CO₂*(1 mol CO₂/ 44 g)*(1 mol C/1 mol CO₂) = 0.01138 mol C
0.01138 mol C*(12 g/mol) = 0.13658 g C

Compute for the amount of H in the compound. The data you need to know are the following:
Molar mass of H = 1 g/mol
Molar mass of H₂O = 18 g/mol
Solution:
0.1282 g H₂O*(1 mol H₂O/ 18 g)*(2 mol H/1 mol H₂O) = 0.014244 mol H
0.014244 mol H*(1 g/mol) = 0.014244 g H

The percent composition of pure hydrocarbon would be:
Percent composition = (Mass of C + Mass of H)/(Mass of sample) * 100
Percent composition = (0.13658 g + 0.014244 g)/(<span>0.1510 g) * 100
</span>Percent composition = 99.88%

2. The empirical formula is determined by finding the ratio of the elements. From #1, the amounts of moles is:

Amount of C = 0.01138 mol
Amount of H = 0.014244 mol

Divide the least number between the two to each of their individual amounts:
C = 0.01138/0.01138 = 1
H = 0.014244/0.01138 = 1.25

The ratio should be a whole number. So, you multiple 4 to each of the ratios:
C = 1*4 = 4
H = 1.25*4 = 5

Thus, the empirical formula of the hydrocarbon is C₄H₅.

3. The molar mass of the empirical formula is

Molar mass = 4(12 g/mol) + 5(1 g/mol) = 53 g/mol
Divide this from the given molecular weight of 106 g/mol
106 g/mol / 53 g/mol = 2
Thus, you need to multiply 2 to the subscripts of the empirical formula.

Molecular Formula = C₈H₁₀

4 0
3 years ago
I know the photo trash but i need answers for the top middle and last question please :)
Firlakuza [10]

Answer:

Middle: Self heating containers are really expensive but are useful because they are easy to use, portable, and can be recycled, unlike a camp stove which is not as easily moved.

Explanation:

i neeed a better image for the first an last boo<3

6 0
2 years ago
Combustion of coal releases sulfur dioxide into the atmosphere. The following process converts this gas into sulfuric acid, a co
Usimov [2.4K]

Answer:

m=7.07gH_{2}SO_{4}

Explanation:

1. Take in account the sulfuric acid at STP:

1840\frac{g}{L}

2. Density is expressed as the ratio between the mass and the volume of a substance so:

d=\frac{m}{V}

Solving for m:

m=\frac{V}{d}

3. Replace values:

m=\frac{1.30*10^{4}L}{1840\frac{g}{L}}

m=7.07gH_{2}SO_{4}

4 0
3 years ago
A solution was prepared by mixing 50.0 g
frez [133]

Answer:

4.78 %.

Explanation:

<em>mass percent is the ratio of the mass of the solute to the mass of the solution multiplied by 100.</em>

<em></em>

<em>mass % = (mass of solute/mass of solution) x 100.</em>

<em></em>

mass of MgSO₄ = 50.0 g,

mass of water = d.V = (0.997 g/mL)(1000.0 mL) = 997.0 g.

mass of the solution = mass of water + mass of MgSO₄ = 997.0 g + 50.0 g = 1047.0 g.

<em>∴ mass % = (mass of solute/mass of solution) x 100</em> = (50.0 g/1047.0 g) x 100 = <em>4.776 % ≅ 4.78 %.</em>

4 0
3 years ago
An iron pipe has a density of 7.86 g/mL and a volume of 324.4 mL. What is the mass of the iron pipe?
wlad13 [49]

Answer:

Mass=2549.784 \ g

Explanation:

The equation for mass is:

Mass = Density * Volume

We plug in the given values into the equation:

Mass = 7.86 \ g/mL * 324.4 \ mL

Mass=2549.784 \ g

6 0
2 years ago
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