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vlabodo [156]
3 years ago
13

The constant k for a certain reaction is measured at two different temperatures:Temperature K376.0°C 4.8x 10^8280.0°C 2.3 x 10^8

Assuming the rate constant obeys the Arrhenius equation, calculate the activation energy E for this reaction.
Chemistry
1 answer:
zaharov [31]3 years ago
3 0

Answer:

Explanation:

548888

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The student who performed this experiment in the question above wrote the following discussion: "The gas sample is known to cont
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What was the experimental measurement of the gas?

Explanation:

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3 years ago
A. True <br> b. False a chemical species is either an acid or a base, it cannot function as both
ivann1987 [24]
False They can function as both. An example is Aluminium Oxide. These kind of substances are called "Amphoteric", they can behave as both acids and bases.
3 0
3 years ago
The Law of Moments is also an equation written as _____.
gayaneshka [121]

Answer:

I think M=rF

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2 years ago
Read 2 more answers
A 1.40-L gaseous system absorbs 75 J of heat and expands its volume to 2.00 L against an external pressure of 1.02 atm. What is
kramer

Answer:

15.24 J is the change in internal energy for this process.

Explanation:

According to the first law of thermodynamics:-

\Delta U = q + w

Where,  

U is the internal energy

q is the heat

w is the work done

From the question,

q = + 75 J

(+ sign as the heat is being absorbed)

The expression for the calculation of work done is shown below as:

w=-P\times \Delta V

Where, P is the pressure

\Delta V is the change in volume

From the question,  

\Delta V = 2.00 - 1.40 L = 0.60 L

P = 1.02 atm

w=-1.02\times0.60\ atmL

Also, 1 atmL = 101.3 J

So,  

w=-1.02\times0.60\times 101.3\ J=-59.76\ J (work is done by the system)

So,

\Delta U = +75\ J-59.76\ J = 15.24\ J

<u>15.24 J is the change in internal energy for this process.</u>

6 0
3 years ago
I need help on this<br>all of them plz
yaroslaw [1]
For the first question it would be a unit obtained from the change in velocity per unit of time or m/s^2.

The vf and vi represent the final and initial velocity of the object and or item.

Knowing the formula for acceleration is simply change in velocity divided by time

Vi = 0
Vf = 27 m/s
t = 10 s

Vf = vi + at

27 = 10a

a = 27/10 or 2.7 m/s^2.
6 0
3 years ago
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