Answer:
<h2>C. </h2>
Explanation:
<h3>#CARRY ON LEARNING</h3><h3>#MARK ON LEARNING</h3><h3>#HELPING HAND</h3>
Answer:
Magnitude of magnetic field is 1.29 x 10⁻⁴ T
Explanation:
Given :
Current flowing through the wire, I = 16.9 A
Length of wire. L = 0.69 m
Magnetic force experienced by the wire, F = 1.5 x 10⁻³ N
Consider B be the applied magnetic field.
The relation to determine the magnetic force experienced by current carrying wire is:
F = ILBsinθ
Here θ is the angle between magnetic field and current carrying wire.
According to the problem, the magnetic field and current carrying wire are perpendicular to each other, that means θ = 90⁰. So, the above equation becomes:
F = ILB
Substitute the suitable values in the above equation.
B = 1.29 x 10⁻⁴ T
Polarized light light is unique in that it vibrates mostly in one direction.
Polarized mild waves are light waves in which the vibrations occur in a single plane. The process of reworking unpolarized light into polarized light is called polarization. There are a ramification of methods of polarizing mild.
Polarization is used for differentiating among transverse and longitudinal waves. Infrared spectroscopy makes use of polarization. it is used in seismology to take a look at earthquakes. In Chemistry, the chirality of organic compounds is tested the use of polarization strategies.
Refraction is the change in route of waves that takes place when waves tour from one medium to every other. . Light has a dual nature. as it has waves, sunlight passing via rainstorm makes a rainbow. however, while mild moves a sun mobile, it can provide strength as a series of very small bursts. particles of count number have names together with the proton, electron and neutron.
Learn more about lights here:-brainly.com/question/19697218
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The friction force is given by:
Where μ is the coefficient of friction (static or kinetic) and
is the normal force. So we say the friction force is directly proportional to the normal force with a constant of proportionality equal to the coefficient of friction.
Work = (force) x (distance)
(550 newtons) x (0.5 meter) = 275 joules each lift .
(275 joules/lift) x (10 lifts) = 2,750 joules of work all together.
Power = (work done) / (time to do the work)
= (2,750 joules) / (20 seconds)
= 137.5 watts . (about 0.18 horsepower)
