Answer:
Explanation:
Given
time taken ![t=2\ s](https://tex.z-dn.net/?f=t%3D2%5C%20s)
Speed acquired in 2 sec ![v=42\ m/s](https://tex.z-dn.net/?f=v%3D42%5C%20m%2Fs)
Here initial velocity is zero ![u=0](https://tex.z-dn.net/?f=u%3D0)
acceleration is the rate of change of velocity in a given time
![a=\frac{v-u}{t}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7Bv-u%7D%7Bt%7D)
![a=\frac{42-0}{2}=21\ m/s^2](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B42-0%7D%7B2%7D%3D21%5C%20m%2Fs%5E2)
Distance travel in this time
![s=ut+0.5at^2](https://tex.z-dn.net/?f=s%3Dut%2B0.5at%5E2)
where
s=displacement
u=initial velocity
a=acceleration
t=time
![s=0+\0.5\times 21\times (2)^2](https://tex.z-dn.net/?f=s%3D0%2B%5C0.5%5Ctimes%2021%5Ctimes%20%282%29%5E2)
![s=42\ m](https://tex.z-dn.net/?f=s%3D42%5C%20m)
so Jet Plane travels a distance of 42 m in 2 s
For astronomical objects, the time period can be calculated using:
T² = (4π²a³)/GM
where T is time in Earth years, a is distance in Astronomical units, M is solar mass (1 for the sun)
Thus,
T² = a³
a = ∛(29.46²)
a = 0.67 AU
1 AU = 1.496 × 10⁸ Km
0.67 * 1.496 × 10⁸ Km
= 1.43 × 10⁹ Km
Answer:
Explanation:
a ) work done by gravitational force
= mg sinθ ( d + .21)
Potential energy stored in compressed spring
= 1/2 k x²
= .5 x 431 x ( .21 )²
= 9.5
According to conservation of energy
mg sinθ ( d + .21) = 9.5
3.2 x 9.8 x sin 30( d + .21 ) = 9.5
d = 40 cm
b )
As long as mg sin30 is greater than kx ( restoring force ) , there will be acceleration in the block.
mg sin30 = kx
3.2 x 9.8 x .5 = 431 x
x = 3.63 cm
When there is compression of 3.63 cm in the spring , block will have maximum velocity. there after its speed will start decreasing.
Answer:
2,352 Joules
Explanation:
At the ground, the barbell has a classical mechanical energy value of zero. There is no classical kinetic or potential energy for the barbell. The moment the man starts to lift the barbell, he does work on the barbell and transfers kinetic energy to it due to the motion. At its maximum height where the man lifts the barbell to a stop, the kinetic energy is zero because it transformed into gravitational potential energy stored in the gravitational field. Our reference point for potential was defined to be zero at the floor, therefore we can say that the gravitational potential energy at 2 meters is:
![U=mgh=(120kg)(9.8m/s^2)(2m)=2,352J](https://tex.z-dn.net/?f=U%3Dmgh%3D%28120kg%29%289.8m%2Fs%5E2%29%282m%29%3D2%2C352J)