Answer:
Explanation:
1 )
Here
wave length used that is λ = 580 nm
=580 x 10⁻⁹
distance between slit d = .46 mm
= .46 x 10⁻³
Angular position of first order interference maxima
= λ / d radian
= 580 x 10⁻⁹ / .46 x 10⁻³
= 0.126 x 10⁻² radian
2 )
Angular position of second order interference maxima
2 x 0.126 x 10⁻² radian
= 0.252 x 10⁻² radian
3 )
For intensity distribution the formula is
I = I₀ cos²δ/2 ( δ is phase difference of two lights.
For angular position of θ1
δ = .126 x 10⁻² radian
I = I₀ cos².126x 10⁻²/2
= I₀ X .998
For angular position of θ2
I = I₀ cos².126x2x 10⁻²/2
= I₀ cos².126x 10⁻²
Answer:
The correct answer is false, a plant dying after being exposed to poison is not a physical change nor is it a physical property.
Explanation:
Answer:
D.
For every action there is an equal and opposite reaction.
Explanation:
im doing the same one lol
Answer:
c) At a distance greater than r
Explanation:
If G= Gravitational constant
M= Mass of earth
r= distance from earth center
then orbital speed is ;
v = 
==> v²=GM/r
If speed of first satellite = V₁
==> V₁² = GM/r
==> r = GM/V₁²
If speed of second satellite say V₂ is less than V₁ then square of V₂ will be less than square of V₁ , and hence GM will be divided by less number in case of second satellite, and hence will give greater value of r as compared to first satellite.
So our answer is c
Answer:
The value is the temperature of the air inside the tire
340.54 K
% of the original mass of air in the tire should be released 99.706 %
Explanation:
Initial gauge pressure = 2.7 atm
Absolute pressure at inlet
= 2.7 + 1 = 3.7 atm
Absolute pressure at outlet
= 3.2 + 1 = 4.2 atm
Temperature at inlet
= 300 K
(a) Volume of the system is constant so pressure is directly proportional to the temperature.


340.54 K
This is the value is the temperature of the air inside the tire
(b). Since volume of the tyre is constant & pressure reaches the original value.
From ideal gas equation P V = m R T
Since P , V & R is constant. So
m T = constant




value of the original mass of air in the tire should be released is

⇒ -0.99706
% of the original mass of air in the tire should be released 99.706 %.