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Ivanshal [37]
2 years ago
7

I will award brainliest...Please what is the work done by a man who is pulling a box of 45kg of mass by means of rope which make

s angle of 45 degrees?
Physics
1 answer:
Minchanka [31]2 years ago
3 0

Answer:

No work is done since no distance is given

Explanation:

Since no distance is given, the force is not doing any work

No work is done by the man since we do not know the distance or displacement.

Work is only said to be done when the force applied on an object moves it through a particular distance.

Work done  = Force x distance.

Since no distance is given in this problem, we can as well assume that the force applied is doing no work on the object.

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What is the SI unit used to mesasure force
lukranit [14]

Answer:

The si unit to measure force are Pascels or Pa

Hope this helps

Please mark me as Brainliest

6 0
3 years ago
Hideki is having trouble completing long workouts. What does he need to improve?
KonstantinChe [14]
He needs to improve his endurance time.
3 0
3 years ago
If the rectangular barge is 3.0 m by 20.0 m and sits 0.70 m deep in the harbor, how deep will it sit in the river?
leva [86]

The harbour contains salt water while the river contains fresh water. So assuming that the densities of fresh water and salt water are:

density (salt water) = 1029 kg / m^3

density (fresh water) = 1000 kg / m^3

The amount of water (in mass) displaced by the barge should be equal in two waters.

mass displaced (salt water) = mass displaced (fresh water)

Since mass is also the product of density and volume, therefore:

<span>[density * volume]_salt water = [density * volume]_fresh water                 ---> 1</span>

 

First we calculate the amount of volume displaced in the harbour (salt water):

V = 3.0 m * 20.0 m * 0.70 m

V = 42 m^3 of salt water

Plugging in the values into equation 1:

1029 kg / m^3 * 42 m^3 = 1000 kg/m^3 * Volume fresh water

Volume fresh water displaced = 43.218 m^3

 

Therefore the depth of the barge in the river is:

43.218 m^3 = 3.0 m * 20.0 m * h

<span>h = 0.72 m        (ANSWER)</span>

8 0
3 years ago
A force of 1.35 newtons is required to accelerate a book by 1.5 meters/second2 along a frictionless surface. What is the mass of
malfutka [58]

B. seems like the answer, I'm not sure.

3 0
3 years ago
Read 2 more answers
Two blocks of ice, one four times as heavy as the other, are at rest on a frozen lake. A person pushes each block the same dista
qaws [65]

Answer:b

Explanation:

Given

mass of heavy object is 4m

mass of lighter object is m

A person pushes each block  with same force F

According to Work Energy theorem Change in kinetic energy of object is equal to Work done by all the object

As launching velocity is same for both the object so heavier mass must possess greater kinetic energy . For same force heavier mass must be pushed 4 times farther than the light block .

\Delta (K.E.)_H=\frac{1}{2}(4m)v^2

\Delta (K.E.)_L=\frac{1}{2}(m)v^2

\Delta K.E.=F\times d

So the correct option is b

4 0
3 years ago
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