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Irina-Kira [14]
3 years ago
13

Pls help for brainliest:)

Physics
1 answer:
Rasek [7]3 years ago
6 0

Answer:

<h2>C. </h2>

Explanation:

<h3>#CARRY ON LEARNING</h3><h3>#MARK ON LEARNING</h3><h3>#HELPING HAND</h3>
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Your go-cart breaks down right before the end of a race, so you have to push it over the finish line. The go-cart has a mass of
Flura [38]

a) W=mg=833 N by definition

b) F=ma=76.5 N according to Newton's second law

c) a=F/m=4.12 m/s^2

d) m=F/a=720/5.5=130.91 kg

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3 years ago
Why is that the hunter can not aim at the fish he can see
poizon [28]

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Heres an image to help

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6 0
3 years ago
What is a tool that can be used to measure the size of a force
Gelneren [198K]

If the force is in the right range ... not too strong and not too
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If the force is huge, then you'd need a truck scale.

If the force is small, then you'd need a laboratory balance.

7 0
4 years ago
Read 2 more answers
A World-class sprinter can reach a top speed of about 11.5 m/s in the first 18.0 m of a race. What is the average acceleration o
irina [24]

Answer

a = 3.674 m / s ^ 2


t = 3.13 s

Using the kinematic equations for the movement we have:


h(t) = P_{0} + Vot + \frac{1}{2}at ^ 2 (1)


V_{f} = V_{0} + at (2)


Where:


P_{0} = initial position


V_{0}} = initial velocity


a = acceleration


t = time in seconds


V_{f} = final speed


We know:


P_{0}=0


V_{0}= 0

h = 18 m


V_{f} = 11.5\frac{m}{s}

  So:

 From (2) we have that: t =\frac{V_{f}}{a}


t =\frac{11.5}{a}

From (1) we have to:


h (t) = 0.5at ^ 2\\h = 18 = 0.5at ^ 2

Then we clear "a" to find the acceleration.


\frac{36}{t^2} = a\\a = \frac{36}{(\frac{11.5}{a})^2} \\\\a =\frac{11.5^2}{36}\\a = 3.674 m / s ^2

Then, the time it takes to reach this speed is:


t =\frac{V_{f}}{a}\\t =\frac{11.5}{3.674}\\t = 3.13 s

4 0
4 years ago
Read 2 more answers
How far can a bike rider traveling at 5.2 m/s go in 15 seconds
frez [133]
If he's traveling at 5.2 m/s, then he covers
5.2 meters in the 1st second
5.2 meters in the 2nd second
5.2 meters in the 3rd second
5.2 meters in the 4th second
.
.
.
.
5.2 meters in the 14th second, and
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He covers 5.2 meters 15 times in 15 seconds.
To find the total distance, you could write down 5.2 meters
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discovered, labor-saving process called 'multiplication' to do
the same thing.  With multiplication, it can be done in one line:

        (5.2 m/s) x (15 sec)  =  78 meters .
7 0
3 years ago
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