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Irina-Kira [14]
3 years ago
13

Pls help for brainliest:)

Physics
1 answer:
Rasek [7]3 years ago
6 0

Answer:

<h2>C. </h2>

Explanation:

<h3>#CARRY ON LEARNING</h3><h3>#MARK ON LEARNING</h3><h3>#HELPING HAND</h3>
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A person jumps forward off the front of a stationary boat floating on a lake. Identify the reaction force in this case, between
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<span>The boat applying a force on the person pushing her forward. 
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3 0
3 years ago
If an object is 30cm in front of a convex mirror that had a focal length of 60cm, how far behind the mirror will the image appea
Darya [45]

Answer: d

Explanation:

had the same study island question

4 0
3 years ago
A ya sorry i don't play ultimate frisbee so ya uhh whats the answer?
Tpy6a [65]

Answer/Explanation:

There can be up to 18 players(for each team) but only 7 players(per team) can be on the field at a time. When in a game there are generally 3 officials.

3 0
3 years ago
A box rests on the back of a truck. The coefficient of friction between the box and the surface is 0.32. (3 marks) a. When the t
cricket20 [7]

Answer:

Part a)

here friction force will accelerate the box in forward direction

Part b)

a = 3.14 m/s/s

Explanation:

Part a)

When truck accelerates forward direction then the box placed on the truck will also move with the truck in same direction

Here if they both moves together with same acceleration then the force on the box is due to friction force between the box and the surface of the truck

So here friction force will accelerate the box in forward direction

Part b)

The maximum value of friction force on the box is known as limiting friction

it is given by the formula

F = \mu mg

so we have

F = ma = \mu mg

now the acceleration is given as

a = \mu g

a = (0.32)(9.8) = 3.14 m/s^2

5 0
3 years ago
A particle is moving along a circular path of 2-m radius such that its position as a function of time is given by u = (5t 2) rad
OverLord2011 [107]

Answer:

Explanation:

Given

radius of  path r=2\ m

Velocity of Particle \theta =5t^2 rad

where t=time in seconds

angular velocity of particle is given by

\omega =\frac{\mathrm{d} \theta }{\mathrm{d} t}

\omega =2\times 5t=10\cdot t

And angular acceleration is given by

\alpha =\frac{\mathrm{d} \omega }{\mathrm{d} t}

\alpha =10 rad/s^2

tangential acceleration is a_t=\alpha \times r

a_t=10\times 2=20\ m/s^2

Centripetal acceleration a_c=\omega ^2\times r

a_c=(10t)^2\times 2=200t^2

net acceleration is sum of tangential and centripetal force at any time t is given by

a_{net}=\sqrt{(a_c)^2+(a_t)^2}

a_{net}=\sqrt{(200t)^2+(20)^2}

a_{net}=20\sqrt{(10t)^2+1}\ m/s

                 

8 0
3 years ago
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