Answer: has properties similar to other elements in group 18, does not react readily with other elements, is part of the noble gas group
Explanation: I’ve done on edg before
Answer:
Refer to attached file below
Hope it helps..
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approximately 1.3 if you calculate it
Answer:
pH = 4.34
Explanation:
pH= -1/2(logKa) -1/2(log C)
= -1/2( log 5.98*10^-8) -1/2(log 0.0353)
=-1/2(-7.22)-1/2(-1.45)
=3.61+0.725= 4.34
Here we have to get the effect of addition of 0.25 moles of gas C on the mole fraction of gas A in a mixture of gas having constant pressure.
On addition of 0.25 moles of C gas, the mole fraction of gas A will be
.
The partial pressure of gas A can be written as
=
×P (where
is the mole fraction of gas A present in the mixture and P is the total pressure of the mixture.
The mole fraction of gas A in a mixture of gas A and C is =
and
respectively.
Thus on addition of 0.25 moles of C gas, the mole fraction of gas A will be
.
Which is different from the initial state.