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zalisa [80]
3 years ago
8

What term refers to the elements in a column of the periodic table

Chemistry
1 answer:
Dennis_Churaev [7]3 years ago
5 0
The term they use is group.
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An electric wire produces a magnetic field. <br><br><br> True or false? (GIVE PROOF)
kupik [55]

Answer:

True

Explanation:

A magnetic field is made when an electric current flows through a wire.

3 0
3 years ago
Determine the molar mass of Ze(NO3)2. (Ze=55.85 N=14.01 O=16.00) *<br> Help
Arturiano [62]

Answer:

179.87 g/mol

Explanation:

First you need to determine the number of each elements in the molecule.  This information comes from the molecular formula.  

Ze(NO3)2 tells us that there is 1 Ze atom and 2 NO3 anions per molecule.  each NO3 anion will have 1 nitrogen and 3 oxygens.  Due to that, one molecule of Ze(NO3)2 will have 1 atom of Ze, 2 atoms of nitrogen (N), and 6 atoms of oxygen (O).

Next you need to add all of the individual atom's molar masses to get the over all molar masses.  The molar masses of each element is in the question but it can also be found on the periodic table.

molar mass of Ze(NO3)2 = 55.85g/mol + (14.01g/mol*2) + (16.00g/mol*6)

molar mass of Ze(NO3)2 = 179.87 g/mol

I hope this helps.

5 0
2 years ago
Write a CER to explain what happened to this styrofoam head. The pics are of the head above water, at a depth of 1000m underwate
statuscvo [17]

Answer:

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Explanation:

im sorry i connot answer your question

4 0
3 years ago
Millimeters, centimeters, meters, kilometers, Inches,<br> feet, and miles are all examples of
siniylev [52]

Answer:

Distance, some kind of distance or length.

Explanation:

 

4 0
2 years ago
The half-life for the radioactive decay of ce−141 is 32.5 days. if a sample has an activity of 3.8 μci after 162.5 d have elapse
Umnica [9.8K]
Answer : 121.5 <span>μCi

Explanation : We have Ce-141 half life given as 32.5 days so if the activity is 3.8 </span><span>μci after 162.5 days of time elapsed we have to find the initial activity.

We can use this formula;

</span>\frac{N}{ N_{0} } =  e^{-( \frac{0.693 X  T_{2} }{T_{1}})

3.8 / N_{0} = e^ ((0.693 X 162.5 ) / 32.5) = 121.5
<span>
On solving we get, The initial activity as 121.5  </span>μci
5 0
2 years ago
Read 2 more answers
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