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Helga [31]
3 years ago
6

Que tanto porciento de 28 es 49?

Mathematics
2 answers:
e-lub [12.9K]3 years ago
7 0

Answer:

24.5

Step-by-step explanation:

Lo pongo a mitad de camino, así que básicamente la mitad de 49 es 24.5

Espero que esto ayude

*I hope this helped*

Si necesita ayuda, hágamelo saber!

*If you need help just let me know*

Que tengas un gran día! :)

kifflom [539]3 years ago
5 0

Answer:

58%

Step-by-step explanation:

Lo siento. No soy bueno con el español, así que estoy usando translate. Espero que esté bien.

Entonces, para esta ecuación, usaremos un porcentaje igual o superior a 100 como se indica aquí. (\frac{es}{de} = \frac{porciento} {100}) Entonces tu ecuación es \frac{28}{49} = \frac{x}{100}

Multiplicará 28 por 100, lo que le dará 2800. Luego, dividiría 2800 entre 48, lo que le daría 58. Entonces, su respuesta sería x = 58%.

Lo siento si no entiende algo de esto porque los traductores no siempre son correctos. Pero espero que esto haya ayudado :)

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\displaystyle -20

Step-by-step explanation:

\displaystyle -9[5] + 3[7] + 4 = -45 + 21 + 4 = -20

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Answer:

  • Domain: All the real values except x = 2 and x = 4: R - {2, 4}
  • Holes: x = 2
  • VA, vertical asymptores: x = 4
  • HA: horizontal asymptotes: there are not horizontal asymptotes
  • OA: oblique asymptotes: x + 6 [note that OH does not stand for any known feature, and so it is understood that it was intended to write OA]
  • Roots: x = 2
  • Y-intercept: -1

Step-by-step explanation:

1. <u>Given</u>:

f(x)=\frac{x^3-8}{x^2-6x+8}

  • Note that the number 8 in the numerator is not part of the power.
  • Type of function: rational function

2. <u>Domain</u>: is the set of x-values for which the function is defined.

The given function is defined for all x except those for which the denominator equals 0.

  • Denominator:  x² -6x + 8 = 0
  • Solve for x:

        Factor. (x - 4 )(x - 2) = 0

        Zero product property: (x - 4) = 0 or (x - 2) = 0

        x - 4 = 0 ⇒ x = 4

        x - 2 = 0 ⇒ x = 2

  • Domain:

        All the real values except x = 2 and x = 4: x ∈ R / x ≠ 2 and x ≠ 4.

3. <u>Holes</u>:

The holes on the graph of a rational function are at those x-values for which both the numerator and denominator are zero.

  • Find the values for which the numerator is zero:

        Numerator: x³ - 8 = 0

        Factor using difference of cubes property:

                   a³ - b³ = (a - b)(a² + ab + b²)

                   x³ - 8 = (x - 2)(x² + 2x + 4) = 0

        Zero product property:  (x - 2)(x² + 2x + 4) = 0

                    x - 2 = 0 ⇒ x = 2                    

                    x² + 2x + 4 = 0 (this has not real solution)

  • The values for which the denominator is zero were determined above: x = 2 and x = 4.

  • Conclusion: for x = 2 both numerator and denominator equal 0, so this is a hole.

4. <u>VA: Vertical asymptotes</u>.

The vertical asymptotes on the graph of a rational function are the vertical lines for which only the denominator (and not the numerator) equals zero.

  • In the previous part it was determined that happens when x = 4.

5. <u>HA: Horizontal asymptotes</u>.

In rational functions, if the numerator is a higher degree polynomial than the denominator, there is no horizontal asymptote.

6. <u>OA: oblique asymptotes</u>

  • Find the quotient and the remainder.

                       x + 6

                  _______________

x² - 6x + 8 )   x³ + 0x² + 0x - 8

                  - x³ + 6x² - 8x

                   ___________

                          6 x² -   8x -  8

                        - 6x² + 36x - 48

                        _____________

                                    28x  - 56

Result: (x + 6) + (28x - 56) / (x² - 6x + 8)

  • Find limit x → ∞

\lim_{x \to \infty}(x + 6) + \frac{28x-56}{x^2-6x+8}=x+6

<u>7. Roots</u>:

Roots are the values for which f(x) = 0.

That happens when the numerator equals 0, and the denominator is not 0.

As determined earlier: x³ - 8 = 0 ⇒ x = 2.

8. <u>Y-Intercept</u>

The y-intercepts of any function are the y-values when x = 0

  • Substitute x = 0 into the function:

         f(x)=\frac{x^3-8}{x^2-6x+8}=\frac{0^3-8}{0^2-6(0)+8}}=\frac{-8}{8} =-1

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3 years ago
What is the reason for statement 4 in the two column proof
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The reason is the gotter of the right angle is 12
5 0
3 years ago
Please help if you can
ArbitrLikvidat [17]

Answer:50

Step-by-step explanation:

All you do is add 60 and 70 together and then subtract what you had got from 180 witch gives you the answer for y and sense x is vertical to y they are going to be the same.

4 0
3 years ago
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