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3 years ago

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What do cations and anions form?

1 answer:

melomori [17]3 years ago

7 0

Answer: Cations (positively-charged ions) and anions (negatively-charged ions) are formed when a metal loses electrons, and a nonmetal gains those electrons. The electrostatic attraction between the positives and negatives brings the particles together and creates an ionic compound, such as sodium chloride.

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C6H1206+5KIO4=5KIO3+5HCO2H+H2CO

Dima020 [189]

Answer:

5 % by mass

Explanation:

1. Calculate the <em>moles of KIO₄</em>.

$\text{Moles of KIO}_{4} = \text{30 mL} \times \frac{\text{0.5 mmol}}{\text{1 mL}} = \text{15 mmol KIO}_{4}$

2. Calculate the <em>moles of sugar</em>

$\text{Moles of sugar} = \text{15 mmol KIO}_{4} \times \frac{\text{ 1 mmol sugar}}{\text{5 mmol KIO}_{4}} = \text{3.0 mmol sugar}$

3. Calculate the <em>mass of sugar</em>

$\text{Mass of sugar} = \text{3.0 mmol sugar} \times \frac{\text{180.16 mg sugar}}{\text{1 mmol sugar}} = \text{540 mg sugar} = \text{0.54 g sugar}$

4. Calculate the <em>mass of the sugar solution</em>

$\text{Mass of solution} = \text{ 10 mL solution} \times \frac{\text{1.10 g solution}}{\text{1 mL solution}} = \text{11.0 g solution}$

5. Calculate the <em>percent by mass</em> of sugar

$\text{\% by mass} = \frac{\text{mass of sugar}}{\text{mass of solution}} \times 100 \%$

$\text{\% by mass} = \frac{\text{0.54 g sugar}}{\text{11.0 g solution}} \times 100 \% = 5 \%$

<em>Note</em>: The answer can have only one significant figure because that is all you gave for the concentration of KIO₄.

6 0

3 years ago

Which substance is an example of an element?

Gnoma [55]

Copper is an element. An element is a substance that is entirely made from one type of atom.

4 0

4 years ago

Read 2 more answers

Is nickel cyanide a ionic or covalent bond

dlinn [17]

Answer:

Ionic

Explanation:

Because there's a metal and nonmetal present in this bond, it is ionic. Covalent bonds occur when there are only metals present. Hope this helps.

3 0

3 years ago

Write balanced equation for:

mario62 [17]

Answer:

hmmm good luck

Explanation:

4 0

2 years ago

If the molar mass of calcium hydroxide (Ca(OH)2) is 74.1 g/mol, how many grams of calcium hydroxide are required to prepare 2.00

Llana [10]

Answer:

88.92 grams of Ca(OH)₂ are required

Explanation:

Molarity means mol/L, so 0.6 M are the moles of solute in 1 L of solution.

In 2 L, we 'll have the double of moles, 1.2

Mol . molar mass = grams

1.2 mol . 74.1 g/m = 88.92 grams of solute

5 0

4 years ago