Answer:
Median highland = 16 mm
Median lowland = 16 mm
Step-by-step explanation:
For the highland area :
The sample size, n = 44
Obtain the median value using :
1/2 * (n + 1)th term
1/2 * (44 +1) th term
1/2 * 45 = 22.5th term.
(22nd + 23rd) term / 2
(16 + 16) / 2 = 16 mm
For the lowland area :
1/2 * (n + 1)th term
1/2 * (44 +1) th term
1/2 * 45 = 22.5th term.
(22nd + 23rd) term / 2
(12 + 12) / 2 = 12 mm
Answer:
please can we see what the question implies?
You are correct! The problems that can arise with a function domain are:
- Denominators that become zero
- Even-degree roots with negative input
- Logarithms with negative or zero input
In this case, you have a denominator, and you don't have roots nor logarithms. This means that your only concern must be the denominator, specifically, it cannot be zero.
And you simply have
![x-3\neq 0 \iff x \neq 3](https://tex.z-dn.net/?f=x-3%5Cneq%200%20%5Ciff%20x%20%5Cneq%203)
So, the domain of this function includes every number except 3.
-2/2 = -1/1 = -1
Therefore, the absolute value of -2/2 is -1.
Area of the Base = 6 * side^2 / 4 * tan (180/6)
Area of the Base = 6 * 16 / 4 * 0.57735
Area of the Base = 96 /
<span>
<span>
<span>
2.3094
</span>
</span>
</span>
Area of the Base =
<span>
<span>
<span>
41.5692387633
</span>
</span>
</span>
Area of 1 Face = 2 * 6 = 12
Area of 6 Faces = 72
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<span>
Total Area = 41.5692387633
</span>
+ 72</span>
Total Area = 113<span>.5692387633</span>