Vertically, the object is in equilibrium, so that the net force in this direction is
∑ <em>F</em> (vertical) = <em>n</em> - <em>mg</em> = 0
where <em>n</em> is the magnitude of the normal force due to the contact between the object and surface. You're given that the object's weight is <em>mg</em> = 550 N, so <em>n</em> = 550 N as well.
Horizontally, the net force would be
∑ <em>F</em> (horizontal) = <em>p</em> - <em>f</em> = 0
where <em>p</em> is the magnitude of the applied force and <em>f</em> is the magnitude of (kinetic) friction opposing <em>p</em>. Now,
<em>f</em> = 0.012<em>n</em> = 0.012 (550 N) = 6.6 N
so that you need to apply a force of <em>p</em> = 6.6 N to keep the object sliding at a steady pace.
The proton. There are three main types of subatomic particles. Protons, Neutrons, and Electrons. Protons are positively charged and found in the nucleus. Neutrons are not charged at all, and found in the nucleus, and electrons are negatively charged and found outside the nucleus in regions known as orbitals.
Answer:
Explanation:
Given
final speed v = 3015ft/s
initial speed = 0m/s
Distance S = 4146m/s
Required
Time
Using the equation of motion to get the time;
S = (v+u)/2 * t
since 1m = 3.28084ft'
4146m = 3.28084 * 4146 = 13,602.36264feet
13,602.36264 = 3015+0/2 * t
13,602.36264 = 1,507.5t
t = 13,602.36264/ 1,507.5
t = 9.023 secs
Hence it will take 9.023 seconds the rescuer die the biller to strike a target
