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Karo-lina-s [1.5K]
3 years ago
13

A car traveling on the highway at 15 m/s accelerates at 3.0 m/s2 for 5.0 s. What is its final velocity?

Physics
1 answer:
Nataly_w [17]3 years ago
3 0

Answer:

The answer to your question is:  vf = 30 m/s

Explanation:

Data

vo = 15 m/s

a = 3.0 m/s²

t = 5 s

vf = ?

Formula

vf = vo + at

Substitution

vf = 15 + (3)(5)

vf = 15 + 15

vf = 30 m/s

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Vinny is on a motorcycle at rest, 200 m away from a ramp that jumps over a gully. Calculate the minimum constant acceleration Vi
soldier1979 [14.2K]

Answer: 6.25 m/s^2

Explanation:

The distance between Vinny and the ramp is 200m

And he has 8 seconds (At max) to reach that distance.

The initial velocity is 0m/s

The initial position is 0m

Now, we want to find the constant acceleration in order to do this, so suppose that we have a constant acceleration A.

a(t) = A.

To have the velocity, we must integrate over time, and remember that the constant of integration is equal to zero because the initial velocity is zero.

v(t) = A*t

For the position, we integrate again over time.

p(t) = 0.5*A*t^2

And we want to travel 200m in 8 seconds, then:

p(8s) = 200m

0.5*A*(8s)^2 = 200m

A*32s^2 = 200m

A = 200m/32s^2 = 6.25 m/s^2

This is the minimum acceleration in order to do this, if Vinny has a larger acceleration he will travel the 200m in a smaller time.

7 0
3 years ago
The top of a swimming pool is at ground level. If the pool is 3.00 m deep, how far below ground level does the bottom of the poo
Yuri [45]

Answer:

a) 2.25 m

b) 2.625 m

Explanation:

Refraction is the name given to the phenomenon of the speed of light changing the the boundary when it moves from one physical medium to the other.

Refractive index is the ratio of the speed of light in empty vacuum (air is an appropriate substitution) to the speed of light in the medium under consideration.

In terms of real and apparent depth, the refractive index is given by

η = (real depth)/(apparent depth)

a) Real depth = 3.00 m

Apparent depth = ?

Refractive index, η = 1.333

1.333 = 3/(apparent depth)

Apparent depth = 3/1.3333 = 2.25 m.

Hence the bottom of the pool appears to be 2.25 m below the ground level.

b) Real depth = 1.5 m

Apparent depth = ?

Refractive index, η = 1.333

1.3333 = 1.5/(apparent depth)

Apparent depth = 1.5/1.3333 = 1.125 m

But the pool is half filled with water, there is a 1.5 m depth on top of the pool before refraction starts.

So, apparent depth of the pool = 1.5 + 1.125 = 2.625 m below the ground level

4 0
3 years ago
A man pulls on his dog's leash to keep him from running after a bicycle. Which term best describes this example?
otez555 [7]
We know the answer doesn't have to do with force because we have not identified a positive or negative axis. 

Depending on what the system we are evaluating is, the sign of the work can change.

If work is done on the system, it is negative, but if work is done by the system, it is positive. 

If the system we are evaluating is the leash, the work is being done by the leash, and therefore, the work is positive.

If the system we are evaluating is the dog, the work is being done on the dog, and therefore, the work is negative.


8 0
3 years ago
Read 2 more answers
What change of state occurs during vaporization? liquid to gas gas to liquid solid to liquid liquid to solid
nignag [31]

Answer:

A is correct!

Explanation:

e2020

8 0
3 years ago
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What's a cars net force if it's mass is 1500 kg and has a acceleration of 2 m/s (In Newton’s)
podryga [215]

Answer: 3,000 N

Explanation:

F = mass x acceleration

F = (1500 kg)(2 m/s²)

F = 3000 N

3 0
3 years ago
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