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3 years ago

A car traveling on the highway at 15 m/s accelerates at 3.0 m/s2 for 5.0 s. What is its final velocity?

Physics

1 answer:

Nataly_w [17]3 years ago

3 0

Answer:

The answer to your question is: vf = 30 m/s

Explanation:

Data

vo = 15 m/s

a = 3.0 m/s²

t = 5 s

vf = ?

Formula

vf = vo + at

Substitution

vf = 15 + (3)(5)

vf = 15 + 15

vf = 30 m/s

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A 5.30kg block hangs from a spring with a spring constant 1700 N/m. The block is pulled down 4.50cm from the equilibrium positio

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To solve this problem it is necessary to apply the concepts related to the frequency in a spring, the conservation of energy and the total mechanical energy in the body (kinetic or potential as the case may be)

PART A) By definition the frequency in a spring is given by the equation

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m = mass

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$f = \frac{1}{2\pi} \sqrt{\frac{1700}{5.3}}$

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PART B) To solve this section it is necessary to apply the concepts related to the conservation of energy both potential (simple harmonic) and kinetic in the spring.

$\frac{1}{2}kA^2 = \frac{1}{2}mv^2 + \frac{1}{2} kY^2$

Where,

k = Spring constant

m = mass

y = Vertical compression

v = Velocity

This expression is equivalent to,

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Our values are given as,

k=1700 N/m

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Replacing we have,

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$E = \frac{1}{2}kA^2$

$E=\frac{1}{2}1700*(0.105)^2$

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