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pishuonlain [190]
3 years ago
13

A proton is ejected from the sun at a speed of 2 x 10^6 m/s. How long does it take for this proton to reach earth? Answer in hou

rs
Physics
1 answer:
wolverine [178]3 years ago
5 0
The distance from the Sun to the Earth is 149,600,000 km.

d=149 600 000 \ km = 149 600 000 000 \ m = 1496 \cdot 10^8 \ m \\
v=2 \cdot 10^6 \ \frac{m}{s} \\ \\ \\
t=\frac{d}{v} \\ \\
t=\frac{1496 \cdot 10^8 \ m}{2 \cdot 10^6 \ \frac{m}{s}}=748 \cdot 10^2 \ s =\frac{748 \cdot 10^2 }{36 \cdot 10^2} \ h \approx \underline{\underline{20,78 \ h}}
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A 2.0 x 10^3-kilogram car travels at a constant speed of 12 meters per second around a circular curve of radius 30. meters. What
Vikentia [17]

The magnitude of the centripetal acceleration of the car as it goes round the curve is 4.8 m/s²

<h3>Circular motion</h3>

From the question, we are to determine the magnitude of the centripetal acceleration.

Centripetal acceleration can be calculated by using the formula

a_{c} =\frac{v^{2} }{r}

Where a_{c} is the centripetal acceleration

v is the velocity

and r is the radius

From the given information

v = 12 \ m/s

and r = 30 \ m

Therefore,

a_{c} =\frac{12^{2} }{30}

a_{c} =\frac{144 }{30}

a_{c} = 4.8\ m/s^{2}

Hence, the magnitude of the centripetal acceleration of the car as it goes round the curve is 4.8 m/s²

Learn more on circular motion here: brainly.com/question/20905151

4 0
2 years ago
A ball is thrown from the top of one building toward a tall building 50 m away. The initial velocity of the ball is 20 m/s at 40
Vinvika [58]

Answer:

Ball hit the tall building 50 m away below 10.20 m its original level

Explanation:

Horizontal speed = 20 cos40 = 15.32 m/s

Horizontal displacement = 50 m

Horizontal acceleration = 0 m/s²

Substituting in s = ut + 0.5at²

    50 = 15.32 t + 0.5 x 0 x t²

     t = 3.26 s

Now we need to find how much vertical distance ball travels in 3.26 s.

Initial vertical speed  = 20 sin40 = 12.86 m/s

Time = 3.26 s

Vertical acceleration = -9.81 m/s²

Substituting in s = ut + 0.5at²

    s = 12.86 x 3.26 + 0.5 x -9.81 x 3.26²

    s = -10.20 m

So ball hit the tall building 50 m away below 10.20 m its original level

5 0
2 years ago
Consider a sample of helium gas in a container fitted with a piston, as pictured below. The piston is frictionless, but has a ma
andrezito [222]

Question:

Consider a sample of helium gas in a container fitted with a piston as pictured below. The piston is frictionless, but has a mass of 10.0 kg. How many of the following processes will cause the piston to move away from the base and decrease the pressure of the gas? Assume ideal behavior.

I. Heating the helium. II.

II. toRemoving some of the helium from the container.

III. Turning the container on its side.

IV. Decreasing the pressure outside the container.

a) 0

b) 1

c) 2

d) 3

e) 4

Answer:

Only one process will cause the piston to move which is

i) Heating the helium

Explanation:

When helium is heated it becomes less dense or lighter. Heating the helium will cause an increase in volume which will make the piston to move away from the base. When the volume finishes increasing, the piston will stop moving which in turn will make the forces on both sides of the piston balanced, so the pressure inside will balance the weight of the piston and that of the atmosphere. From that we can see that there has been a pressure change as a result of heating.

6 0
3 years ago
Read 2 more answers
We run a distance of 1000 m at a speed of 4.3 m/s. Calculate the time elapsed to cover this distance
pashok25 [27]

Answer:

So if we need to cover 1000 meters. And we go at a speed of 4.3 m/s. That means that every 4.3 meters we cover is 1 second. So we divide both amd get

1000/4.3 = 232.56 is approx the answer. Also the meters cancel out because

m/(m/s) = m*s/m, cancels out giving s as a unit.

<h2><u>Therefore the answer is 232.56 seconds</u></h2>

6 0
3 years ago
When you cook a marshmallow on a metal poker tool over an open flame, energy is transferred. Identify the three different ways t
sergejj [24]

Answer:

The three ways thermal energy is transferred are;

1) Conduction

2) Convection

3) Radiation

Explanation:

1) The conduction of the heat from the open flame to the marshmallow is through the direct contact of the flame with the marshmallow, such that the flame the region of the combustion reaction, that produces light and heat touches the marshmallow

2) The convection process is the transfer of heat from the rising heated combustion products, as well as the heated air that rises from the flame

3) The radiation heat transfer is the transfer of the heat from the fire to the marshmallows directly by the heat the moves in the form of electromagnetic waves at temperatures above 1000 K, without the need for a medium, such that the marshmallow can be heated by the heat coming from side of the flame.

4 0
3 years ago
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