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2 years ago

What is equal to the number of particles in 36 grams of carbon-12?

Chemistry

1 answer:

HACTEHA [7]2 years ago

4 0

Answer:

3 moles

Explanation:

To solve this problem we will use the Avogadro numbers.

The number 6.022×10²³ is called Avogadro number and it is the number of atoms, ions or molecules in one mole of substance. According to this,

1.008 g of hydrogen = 1 mole = 6.022×10²³ atoms.

18 g water = 1 mole = 6.022×10²³ molecules

we are given 36 g of C-12. So,

12 g of C-12 = 1 mole

24 g of C-12 = 2 mole

36 g of C-12 = 3 mole

So 3 moles of C-12 equals to the number of particles in 36 g of C-12.

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If you have an aqueous solution that contains 1.5 moles of hcl, how many moles of ions are in the solution? (a) 1.0, (b) 1.5, (c

Darya [45]

If you have an aqueous solution that contains 1.5 moles of HCl, the number of moles of ions in the solution is 3.0 moles.

<h2>Further Explanation </h2><h3>Strong acids </h3>

Strong acids are types of acids that undergo complete dissociation to form ions when dissolved in water.
Examples of such acids are, HCl, H2SO4 and HNO3
Dissociation of HCl

HCl + H₂O ⇔ H₃O⁺ + OH⁻

<h3>Weak acids </h3>

Weak acids are types of acids that undergo incomplete dissociation to form ions when dissolved in water.
Examples of such acids are acetic acids and formic acids.
Dissociation of acetic acid

H₃COOH ⇔ CH₃COO⁻ + H⁺; CH₃COO⁻ is a conjugate base of acetic acid.

HCl which is a strong acid that ionizes completely according to the equation;

HCl + H₂O ⇔ H₃O⁺ + OH⁻

From the equation, 1 mole of HCl produces 1 mole of H₃O⁺ ions and 1 mole of OH⁻ ions.

Therefore;

1.5 moles of HCl will produce;

= 1.5 moles of H₃O⁺ ions and 1.5 moles of OH⁻ ions.

This gives a total number ions of;

= 1.5 + 1.5

= 3 moles of ions

Keywords: Strong acid, weak acid, ions, ionization

<h3>Learn more about: </h3>

Strong acid: brainly.com/question/3239966
Weak acid; brainly.com/question/3239966
Ionization of acids and bases: brainly.com/question/11844503

Level: High school

Subject: Chemistry

Topic: Salts, Acids and Bases

6 0

2 years ago

Read 2 more answers

What is the predominant intermolecular force in CBr4

vovikov84 [41]

CBr4 is a symmetric tetrahedral molecule so it will be non-polar.

3 0

3 years ago

How many moles of HCl are found in 500mL of HCl solution with pH of 3

Alexxx [7]

Answer:

Number of moles = 0.0005 mol.

Explanation:

Given data:

pH = 3

Volume of solution = 500 mL

Number of moles = ?

Solution:

HCl dissociate to gives H⁺ and Cl⁻

HCl → H⁺ + Cl⁻

It is known that,

pH = -log [H⁺]

3 = -log [H⁺]

[H⁺] = 10⁻³ M

[H⁺] = 0.001 M

Number of moles of HCl:

Molarity = number of moles / Volume in litter

Number of moles = Molarity × Volume in litter

Number of moles = 0.001 mol/L × 0.5 L

Number of moles = 0.0005 mol

7 0

3 years ago

___CH4 + ___O2 → ___CO2 + ___H2O

DaniilM [7]

CH4 + 2O2 =======> CO2 + 2H2O

5 0

2 years ago

A tablet of Pain Be Gone Aspirin, which had a mass of 1.213 g, was pulverized and 1.159 g were dissolved in 10.0 mL of ethyl alc

Elan Coil [88]

Answer:

a. Moles of $NaOH$ = 0.001643 moles

b. 0.296 g

c. 0.3098 g

d. Not acceptable

Explanation:

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Or,

$Moles =Molarity \times {Volume\ of\ the\ solution}$

Given :

For $NaOH$ :

Molarity = 0.1052 M

Volume = 15.62 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 15.62×10⁻³ L

Thus, moles of $NaOH$ :

$Moles=0.1052 \times {15.62\times 10^{-3}}\ moles$

Moles of $NaOH$ = 0.001643 moles

The reaction of NaOH with the acetylsalicylic acid is in the ratio of 1:1.

Thus, Moles of NaOH = Moles of acetylsalicylic acid = 0.001643 moles

Molar mass of acetylsalicylic acid = 180.16 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

Mass = Moles * Molar mass = 0.001643 moles * 180.16 g/mol = 0.296 g

1.159 g of sample contains 0.296 g of acetylsalicylic acid

1.213 g of sample contains $\frac{0.296}{1.159}\times 1.213$ g of acetylsalicylic acid

Mass of acetylsalicylic acid = 0.3098 g = 309.8 mg

d. Sample contains = 309.8 mg

Manufacturer claiming = 315 mg to 335 mg

Thus , it is not acceptable.

5 0

3 years ago