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Mars2501 [29]
3 years ago
11

The Earth experiences an ice age when the overall climate becomes much cooler. During an ice age, there are several periods of g

laciation, which are periods when glaciers and ice sheets cover more of the Earth's surface. Ice reflects more sunlight back into outer space than does bare or vegetated ground. Because ice sheets and glaciers are more reflective, they absorb less sunlight and therefore release _______ heat. This causes the Earth's climate to become _______ during periods of glaciation.
Chemistry
2 answers:
Anettt [7]3 years ago
6 0

The given blank can be filled with less and even cooler.

A long duration of decline in the temperature of the surface of the Earth and atmosphere, leading to the expansion or existence of the polar and continental ice sheets and alpine glaciers is known as an ice age.  

During an ice age, there are many periods of glaciation that are periods when ice sheets and glaciers cover the majority of the Earth's surface.  

The ice reflects more sunlight back into outer space than does the vegetated or bare ground. As the glaciers and ice sheets are more reflective, they captivate less sunlight and thus discharge less heat. This makes the climate of the Earth to become even cooler during the times of glaciation.  


ladessa [460]3 years ago
6 0

Answer: less and even cooler

Explanation: i just did it on my study island

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ipn [44]

<u>Answer:</u>

<u>For 2:</u> The % yield of the product is 92.34 %

<u>For 3:</u> 12.208 L of carbon dioxide will be formed.

<u>Explanation:</u>

  • <u>For 2:</u>

The percent yield of a reaction is calculated by using an equation:

\% \text{yield}=\frac{\text{Actual value}}{\text{Theoretical value}}\times 100              ......(1)

Given values:

Actual value of the product = 78.4 g

Theoretical value of the product = 84.9 g

Plugging values in equation 1:

\% \text{yield}=\frac{78.4 g}{84.9g}\times 100\\\\\% \text{yield}=92.34\%

Hence, the % yield of the product is 92.34 %

  • <u>For 3:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(2)

Given mass of carbon dioxide = 24 g

Molar mass of carbon dioxide = 44 g/mol

Plugging values in equation 1:

\text{Moles of carbon dioxide}=\frac{24g}{44g/mol}=0.545 mol

<u>At STP conditions:</u>

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