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omeli [17]
3 years ago
12

When a volcano​ erupts, the height of the peak is reduced and the upper portion is removed. The height of a volcano after it eru

pted was​ 8,219.5 feet. This was​ 85% of the​ volcano's original height. What was the original​ height?
(answer this and show your work please thank you)
The original height was _answer this_ feet.

please help me with this thank you
Mathematics
1 answer:
ANTONII [103]3 years ago
4 0

Answer:

9670 feet

Step-by-step explanation:

The height given (8219.5 ft) is 85% OF ORIGINAL, hence original is much higher. But how do we figure this out?

we translate word problem to equation.

8219.5 IS 85% of TOTAL

Firstly, 85% = 85/100 = 0.85

Remember, is means =

of means multiplication

So we have:

8219.5 = 0.85 * Total

Hence, total = [let total be 7]

8219.5 = 0.85 * t

t = 8219.5/0.85 = 9670 feet

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klemol [59]

Answer:

angle D is 90⁰

E is 66⁰

and F is 114⁰

7 0
3 years ago
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Leo bought a used car for x dollars. one year later the value of the car was 0.88x. which expression is another way to describe
Lesechka [4]

Initial price of car = $x

After one year the price of car = $0.88x

to find the change in price we subtract the price after one year from initial price.

It means change in price = (x-0.88x)= 0.12x

By this we can easily see that , price dropped by 0.12

Or we can say that price dropped by 12%


So option C is the correct answer

C) 12% decrease

7 0
4 years ago
If x + 4 = 32, does x = 8?
miss Akunina [59]

Answer:

No

Step-by-step explanation:

I say no because if we were to replace x with 8, the equation should look like this = 8 + 4 = 32. Since this doesn't make sense, 8 cannot be x. X would be 28 which would equal 32 and would be the right answer.

7 0
3 years ago
Find the average velocity of the function over the given interval 2+tan x[-pi/4
Andreyy89
2+tan ×[-pi/4

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7 0
4 years ago
1. The national mean (μ) IQ score from an IQ test is 100 with a standard deviation (s) of 15. The dean of a college wants to kno
Nat2105 [25]

Answer:

We conclude that the mean IQ of her students is different from the national average.

Step-by-step explanation:

We are given that the national mean (μ) IQ score from an IQ test is 100 with a standard deviation (s) of 15.

The dean of a college want to test whether the mean IQ of her students is different from the national average. For this, she administers IQ tests to her 144 students and calculates a mean score of 113

Let, Null Hypothesis, H_0 : \mu = 100 {means that the mean IQ of her students is same as of national average}

Alternate Hypothesis, H_1 : \mu\neq 100  {means that the mean IQ of her students is different from the national average}

(a) The test statistics that will be used here is One sample z-test statistics;

               T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ N(0,1)

where, Xbar = sample mean score = 113

              s = population standard deviation = 15

             n = sample of students = 144

So, test statistics = \frac{113-100}{\frac{15}{\sqrt{144} } }

                             = 10.4

Now, at 0.05 significance level, the z table gives critical value of 1.96. Since our test statistics is more than the critical value of z which means our test statistics will fall in the rejection region and we have sufficient evidence to reject our null hypothesis.

Therefore, we conclude that the mean IQ of her students is different from the national average.

3 0
4 years ago
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