Question

What is the electric field strenght in units of N/C if the flux through a 2.0m by 1.0m rectangular surface is 396Nm2/C, if the electric field is uniform, and if the plane of the surface is at an angle of π/3 radians with respect to the direction of the field ?

Answer 1

Answer:

The appropriate answer is "396 N/C".

Explanation:

The give values are:

Rectangular surface,

$\Phi_e=396 \ N.m^2/C$

$a = 2 \ m$

$b = 1 \ m$

Angle,

$\theta =\frac{\pi}{3} \ radian$

Now,

The area of rectangle (A) will be:

=  $a\times b$

=  $2\times 1$

=  $2 \ m^2$

hence,

The electric field strength will be:

⇒  $\Phi_e=E.A Cos \theta$

or,

⇒  $E=\frac{\Phi_e}{ACos \theta}$

On putting the given values, we get

⇒      $=\frac{396}{2\times Cos(\frac{\pi}{3} )}$

⇒      $=\frac{396}{2\times 0.5}$

⇒      $=\frac{396}{1}$

⇒      $=396 \ N/C$