Answer:
1.5 times
Explanation:
= depth of the diver initially = 5 m
= density of seawater = 1030 kg m⁻³
= Initial pressure at the depth
= final pressure after rising = 101325 Pa
Initial pressure at the depth is given as
= Initial volume at the depth
= Final volume after rising
Since the temperature remains constant, we have
1) Velocity: 9.9 m/s and 14 m/s
The motion of the diver is a free-fall motion, so it is a uniform accelerated motion. Choosing downward as positive direction, the final velocity can be found by using the following suvat equation:
where
v is the final velocity
u = 0 is the initial velocity (the diver starts from rest)
is the acceleration of gravity
s is the displacement
For the diver jumping from 5 m, s = 5 m, so
For the diver jumping from 10 m, s = 10 m, so
2) Time: 1.01 s and 1.43 s
The time of flight of each diver can be found by using the other suvat equation
And since u = 0, it can be reduced to
For the diver jumping from 5 m, s = 5 m, so we find
For the diver jumping from 10 m, s = 10 m, so we find