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oee [108]
3 years ago
8

PLease help me please

Mathematics
1 answer:
valkas [14]3 years ago
7 0
Xy+24=x22 that is the answer hope it helps
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In which cell structure does MOST of the process of cellular respiration take place?A.nucleusB.vacuoleC.cell wallD.mitochondrion
Zielflug [23.3K]

Mitochondria, therefore D

5 0
3 years ago
The table below represents the displacement of a bird from its nest as a function of time: time (hours) x displacement from nest
zubka84 [21]
Answer: See each part below.

Part A: The y-intercept is the first value, or 12. That means that they bird is 12 miles from its nest when the time started.

Part B: The average rate of change is the slope. From 1 to 3 hours, the bird went from 20 to 36 or 16 miles. 16 miles in 2 hours is the same as 8 miles in 1 hour.

Part C: To find the extent of the domain, write and solve the following equation for 172 miles.
172 = 8x + 12
160 = 8x 
20 = x

The domain will go up to 20 hours.
3 0
3 years ago
State a true conclusion. 1) If two planes intersect, their intersection is a line. 2) Plane R and plane S intersect. Conclusion:
Vesna [10]

Two planes that intersect are simply called a plane to plane intersection. When they intersect, the intersection point is simply called a line.

Therefore, Plane R and Plane S form a line when they intersect.

4 0
3 years ago
Read 2 more answers
Can someone help pls.
kap26 [50]

<em>My goodness, this is rather confusing in the way it is worded. Nevertheless, I will attempt to do what I can. Just please keep in mind that this is my own interpretation of the problem, and therefore could be... incorrect.</em>

<em>I think, to start out, we could set up the problem like so</em>

<em>15 + t ≥ 26</em>

<em>because t is not a set number. </em>

<em>Then all that is needed is to subtract 15 from both sides, and the equation becomes</em>

<em>t ≥ 11</em>

<em>So the resulting answer is t ≥ 11.</em>

<em />

<em>I hope that my interpretation helps.</em>

<em>-Toremi</em>

<em />

8 0
2 years ago
Read 2 more answers
Mr. Paulsen challenges Olivia and Angelica to move figure ABCDE onto figure A"B"C"D"E" using a series of two different transform
Jobisdone [24]

Problem 1

One method Olivia could have used is to reflect over the x axis and then translate 10 units to the right.

Let's apply these set of steps to point C.

C = (-2,-4)

C' = (-2,4) after reflecting over the x axis; y coordinate flips in sign

C'' = (8,4) after shifting to the right 10 units; add 10 to the x coordinate

Point C(-2,-4) moves to C''(8,4) which is shown in the diagram. I'll let you check the other four points.

-----------

Another method Olivia could have used is to shift to the right 10 units first, then reflect over the x axis. In this case, the order doesn't matter. Though for some other combinations of transformations, order does matter.

============================================================

Problem 2

Reflecting over the y axis will have the point (x,y) turn into (-x,y). Only the x coordinate changes, and we flip the sign here. The y coordinate stays the same.

A point like C(-2,-4) becomes C'(2,-4) after the y axis reflection. Shifting up 8 units means we add 8 to the y coordinate to arrive at C''(2,4) but this does not match what the diagram shows. Therefore, Angelica's method is incorrect.

You should find other inconsistencies for the other four points as well.

============================================================

Problem 3

Michael's method isn't correct either. He does not apply an x axis reflection and instead relies entirely on translations to move ABCDE to A''B''C''D''E''

At a quick glance, it looks like Michael may be correct. But upon a much closer look, you'll see that things don't line up perfectly.

Instead of point C, we'll pick on point D this time.

D is located at (-6,-2). If we shift up 8 units, then we add 8 to the y coordinate to get to D'(-6,6). Then add 10 to the x coordinate to shift 10 units to the right. This leads us to D''(4,6).

However, the diagram shows D'' is actually at (4,2)

I'll let you check the other points. You should find that only points C and E go to the correct locations, but the other points do not. Again, this is because Michael did not apply an x axis reflection. His figure of A''B''C''D''E'' is upside down compared to what it should be.

============================================================

To summarize, the methods described in problem 1 are the correct way to get ABCDE to move to A''B''C''D''E''. If Olivia followed either of those two methods, then she is correct. Both Angelica and Michael have incorrect methods.

5 0
2 years ago
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