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Anestetic [448]
3 years ago
5

a physical science textbook has a mass of 2.2 kg. If the textbook weighs 19.6 newtons on Venus, what is the strength of gravity

on that planet?
Physics
2 answers:
nadezda [96]3 years ago
8 0
112244798978957866777777888844322123445545
Juli2301 [7.4K]3 years ago
6 0

Answer:

The strength of gravity on Venus is 8.91m/s².

Explanation:

The strength of gravity on a planet is given by the following formula:

g = w/m

In which w is the weight, in newtons, and m is the mass, in kg.

In this problem, we have that:

Textbook weighs 19.6 newtons on Venus.

This means that w = 19.6

mass of 2.2 kg

So m = 2.2

What is the strength of gravity on that planet?

g = w/m = 19.6/2.2 = 8.91

The strength of gravity on Venus is 8.91m/s².

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The answer should be B. A half step

8 0
3 years ago
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1. A man throws a ball up with a velocity of 30 m/s. How high does it get?
ElenaW [278]
Yes the answer is g=5
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3 years ago
Um objeto de 4cm de altura está a 30cm de um espelho côncavo, cujo raio de curvatura tem valor absoluto de 20cm.
Shkiper50 [21]

a) The distance of the image from the mirror is 15 cm

b) The size of the image is -2 cm (inverted)

Explanation:

a)

We can solve this first part of the problem by applying the mirror equation:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where

f is the focal length

p is the distance of the object from the mirror

q is the distance of the image from the mirror

For a mirror, the focal length is half the radius of curvature, R:

f=\frac{R}{2}

For this mirror, R = 20 cm, so its focal length is

f=\frac{20}{2}=+10 cm (positive for a concave mirror)

Here we also know:

p = 30 cm is the distance of the object from the mirror

So, by applying the equation, we can find q:

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{10}-\frac{1}{30}=\frac{1}{15} \rightarrow q = 15 cm

b)

We can solve this part by using the magnification equation:

M=-\frac{y'}{y}=\frac{q}{p}

where

y' is the size of the image

y is the size of the object

q is the distance of the image from the mirror

p is the distance of the object from the mirror

Here we have:

q = 15 cm

p = 30 cm

y = 4 cm

Solving for y', we find the size of the image:

y'=-y\frac{q}{p}=-(4)\frac{15}{30}=-2 cm

and the negative sign means that the image is inverted.

#LearnwithBrainly

6 0
3 years ago
1. What are the units of area under the line/curve?<br> 2. Does the area have any meaning?
TiliK225 [7]

The area under the velocity time graph is 125 m and the meaning of the area is displacement.

<h3>What is area under velocity - time graph?</h3>

The area under a velocity time graph represents the displacement of the object.

total area of the graph = A1 + A2

total area of the graph = ¹/₂ (base₁)(height₁) + ¹/₂ (base₂)(height₂)

total area of the graph = ¹/₂(4)(40) + ¹/₂(3)(30)

total area of the graph = 125 m

Thus, the area under the velocity time graph is 125 m and the meaning of the area is displacement.

Learn more about velocity time graph here: brainly.com/question/4710544

#SPJ1

6 0
2 years ago
How much energy is produced if you have a current carrying a charge of 0.0006 C running 8.0 V?
sweet-ann [11.9K]

Answer:

Energy= Workdone = 1/2QV

= 1/2x0.0006 x 8

=2.4x10-³J.

5 0
3 years ago
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