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Anestetic [448]
3 years ago
5

a physical science textbook has a mass of 2.2 kg. If the textbook weighs 19.6 newtons on Venus, what is the strength of gravity

on that planet?
Physics
2 answers:
nadezda [96]3 years ago
8 0
112244798978957866777777888844322123445545
Juli2301 [7.4K]3 years ago
6 0

Answer:

The strength of gravity on Venus is 8.91m/s².

Explanation:

The strength of gravity on a planet is given by the following formula:

g = w/m

In which w is the weight, in newtons, and m is the mass, in kg.

In this problem, we have that:

Textbook weighs 19.6 newtons on Venus.

This means that w = 19.6

mass of 2.2 kg

So m = 2.2

What is the strength of gravity on that planet?

g = w/m = 19.6/2.2 = 8.91

The strength of gravity on Venus is 8.91m/s².

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Explanation:

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What type of charges attract each other
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opposite charges attract each other while same charges repel each other.

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3 years ago
A 4 cm diameter "bobber" with a mass of 3 grams floats on a pond. A thin, light fishing line is tied to the bottom of the bobber
Tasya [4]

Answer:

Explanation:

Calculate the volume of the lead

V=\frac{m}{d}\\\\=\frac{10g}{11.3g'cm^3}

Now calculate the bouyant force acting on the lead

F_L = Vpg

F_L=(\frac{10g}{11.3g/cm^3} )(1g/cm^3)(9.8m/s^2)\\\\=8.673\times 10^{-3}N

This force will act in upward direction

Gravitational force on the lead due to its mass  will act in downward direction

Hence the difference of this two force

T=mg-F_L\\\\=(10\times10^{-3}kg(9.8m/s^2)-8.673\times 10^{-3}\\\\=8.933\times10^{-3}N

If V is the volume submerged in the water then bouyant force on the bobber is

F_B=V'pg

Equate bouyant force with the tension and gravitational force

F_B=T_mg\\\\V'pg=\frac{(8.933\times10^{-2}N)+mg}{pg} \\\\V'=\frac{(8.933\times10^{-2}N)+mg}{pg}

Now Total volume of bobble is

\frac{V'}{V^B} =\frac{\frac{(8.933\times10^{-2})+Mg}{pg} }{\frac{4}{3} \pi R^3 }\times100\\\\=\frac{\frac{(8.933\times10^{-2})+(3)(9.8)}{(1000)(9.8)} }{\frac{4}{3} \pi (4.0\times10^{-2})^3 }\times100\\\\

=\large\boxed{4.52 \%}

7 0
3 years ago
A body of mass 2kg moves round a circle of radius 5m with a constant speed of 10m/s. Calculate the force toward the centre of th
antiseptic1488 [7]

Answer:

F = 5

Explanation:

F = m x v^2/r = 2 x 10^2/5 =200/5 = 40 (N)

5 0
2 years ago
Light requires 4.5 years to travel from the nearest star to earth. If we could travel there in a spaceship going 90% of the spee
weeeeeb [17]

Answer:

Time according to earth clock (T0) = 0.22 years (Approx)

Explanation:

Given:

Time taken by light = 4.5 years

Time taken by ship = 5 years

Speed of light = c

Speed of ship (v) = 90% of c = 0.9c

Find:

Time according to earth clock (T0) = ?

Computation:

Time dilation is ,

T(Difference) = \frac{T0}{\sqrt{1-\frac{v^2}{c^2} } }\\\\ (5-4.5)= \frac{T0}{\sqrt{1-\frac{(0.9c)^2}{c^2} } }\\\\ 0.5=\frac{T0}{\sqrt{1-0.81} }\\\\T0 =0.2179

Time according to earth clock (T0) = 0.22 years (Approx)

7 0
3 years ago
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