Emf e = 11
r 1 = 3.0
r 2 = 3.0
r 3 = ?
The two in parallel are equivalent to 3 • 3/6 = 1.5 Ω
To have 2.4 volts across them, the current is I = 2.4/1.5 = 1.6 amps. and the unknown R = (11–2.4) / 1.6 = 5.375 Ω or 5.4 Ω
Answer:
21.6 kN
Explanation:
F = m * a
F = 54 000 * .4 = 21600 N
Answer:
50m/s, 187.5m
Explanation:
Consider unit analysis:
m/s² = m/(s×s)
This can be read as "meters per second, per second". From fundamental kinematics, meters per second is the same as saying velocity.
Velocity is being increased per second, and this is called acceleration:
a = v/t, where a is acceleration, v is change of velocity and t is change of time. "Change" is represented by a triangle called delta and (delta)A = A2 - A1
From the question, we have the variables:
a = 5m/s²
(delta)v = v2 - 25m/s
(delta)t = 5s (initial time is 0)
a = v/t
(5m/s^2)=v/5s
25m/s = v2 - 25m/s
50m/s = v2
The final velocity of the vehicle is 50m/s.
A formula exists to find displacement with regards to acceleration:
d=v(initial) × t +1/2 × a × t²
d=25m/s × 5s + 1/2 × 5m/s² ×(5s)²
d=125m+1/2×125m
d=125m+62.5m
d=187.5m
The distance travelled by the vehicle is 192.5m.
<em>One of the most important skills you can have in any science is unit analysis. Treat meters, seconds, moles, etc as </em><em>values</em><em> when doing </em><em>calculations</em><em> </em><em>and see if you get the result you're looking for.</em>
Answer:
<h2> $1.50</h2>
Explanation:
Given data
power P= 2 kW
time t= 15 min to hours = 15/60= 1/4 h
cost of power consumption per kWh= 10 cent = $0.1
We are expected to compute the cost of operating the heater for 30 days
but let us computer the energy consumption for one day
Energy of heater for one day= 2* 1/4 = 0.5 kWh
the cost of operating the heater for 30 days= 0.5*0.1*30= $1.50
<u><em>Hence it will cost $1.50 for 30 days operation</em></u>
Pretty sure the answer is B. Attract each other
