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3 years ago

Can someone help me with this please?

Physics

1 answer:

Nikolay [14]3 years ago

4 0

Answer:

Explanation:

umm... try 30

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Find the potential energy of a 40kg cart that is on a hill that is 10 meters high

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Explanation:

P.E. = mgh

PE = 40 × 10 × 10

PE = 4000 Joule

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2 years ago

You are pushing a heavy box across a rough floor. when you are initially pushing the box and it is accelerating, (a) you exert a

kodGreya [7K]

The answer is C. If the box is accelerating, that means that the amount of force you are exerting is greater than the force of the box.

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3 years ago

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A particular lightbulb is designed to consume 40 W when operating on a car's 12-V DC electric power. If you supply that bulb wit

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40V because it will provide the same amount of power.

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2 years ago

A(n) 7.7-kg object is sliding across the ice at 2.34 m/s in the positive x direction. An internal explosion occurs, splitting th

-BARSIC- [3]

Answer:

Average acceleration on first part of the chunk is given as

$a_1 = 13.125 m/s^2$

Average acceleration on second part of the chunk is given as

$a_2 = -13.125 m/s^2$

Explanation:

By momentum conservation along x direction we will have

$mv_i = \frac{m}{2}v_1 + \frac{m}{2}v_2$

so we have

$v_1 + v_2 = 2v$

$v_1 + v_2 = 4.68$

also by energy conservation

$\frac{1}{2}(\frac{m}{2})v_1^2 + \frac{1}{2}(\frac{m}{2})v_2^2 - \frac{1}{2}mv^2 = 17 J$

$\frac{1}{4}m(v_1^2 + v_2^2) - \frac{1}{2}mv^2 = 17$

$(v_1^2 + v_2^2) - 2v^2 = \frac{4}{7.7}(17)$

$(4.68 - v_2)^2 + v_2^2 - 2v^2 = 8.83$

$21.9 + 2v_2^2 - 9.36 v_2 - 10.95 = 8.83$

$2v_2^2 - 9.36v_2 + 2.12 = 0$

by solving above equation we will have

$v_1 = 4.44 m/s$

$v_2 = 0.24 m/s$

Average acceleration on first part of the chunk is given as

$a_1 = \frac{4.44 - 2.34}{0.16}$

$a_1 = 13.125 m/s^2$

Average acceleration on second part of the chunk is given as

$a_2 = \frac{0.24 - 2.34}{0.16}$

$a_2 = -13.125 m/s^2$

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3 years ago

What is the slope of (0,0)(4,200)

Kruka [31]

Answer:

.02

Explanation:

X-x/ Y-y= 4-0/200-0 =.02

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3 years ago

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Can someone help me with this please?​

Can someone help me with this please?