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3 years ago

5

Which is the slope-intercept form of the equation of a line that passes through (5,-4) and has a slope of 3/4

1 answer:

Andreas93 [3]3 years ago

4 0

Y = mx +b whre m is the slope and b is the y-intercept.

We have the slope 3/4 so put that instead of m

y = 3/4x + b

Now to find the y-intercept (b), plug the ordered pair in and solve for b.

-4 = 3/4 * 5 + b
-4 = 15/4 + b
-31/4 + b

So y = 3/4x - 31/4

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Solve for x in the triangle round your answer to the nearest tenth <br> Pls help ASAP!!

lbvjy [14]

Answer:

x = 3.9

Step-by-step explanation:

cos = adj/hyp

cos67 = x/ 10

x = 10 * cos67

use calculator

x = 3.9

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2 years ago

An angle measures 64.8° less than the measure of its complementary angle. What is the measure of each angle?

kirill115 [55]

Answer:

<u>77.4 degrees and 12.6 degrees</u>

Step-by-step explanation:

Let the angles be x and x - 64.8.

Therefore, on the basis of knowledge that complementary angles add up to 90 degrees :

x + x - 64.8 = 90

2x = 154.8

x = <u>77.4 degrees</u>

x - 64.8 = 77.4 - 64.8 = <u>12.6 degrees</u>

5 0

2 years ago

8.) What is the probability of rolling a 2 on a six-sided number cube and flipping heads on a coin? *

Leto [7]

The probability of rolling a 3 on a six sided number cube is 1/6

4 0

3 years ago

The area of ABED is 49 square units. Given AGequals9 units and ACequals10 units, what fraction of the area of ACIG is represent

stiks02 [169]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

$A=b^{2}$

where b is the length side of the square

we have

$A=49\ units^2$

substitute

$49=b^{2}$

$b=7\ units$

therefore

$AB=BE=ED=AD=7\ units$

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

$A=(AC)(AG)$

substitute the given values

$A=(9)(10)=90\ units^2$

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

$A=(DE)(DG)$

we have

$DE=7\ units$

$DG=AG-AD=9-7=2\ units$

substitute

$A=(7)(2)=14\ units^2$

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

$A=(EF)(CF)$

we have

$EF=AC-AB=10-7=3\ units$

$CF=BE=7\ units$

substitute

$A=(3)(7)=21\ units^2$

step 5

sum the shaded areas

$14+21=35\ units^2$

step 6

Divide the area of of the shaded region by the area of ACIG

$\frac{35}{90}$

Simplify

Divide by 5 both numerator and denominator

$\frac{7}{18}$

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

5 0

3 years ago

I don’t know this one

torisob [31]

Answer:

3077.2

Step-by-step explanation:

A circle's mass is found by

Pie times R^2

7^2 is 49, times 3.14 is 153.86

then you Multiply 153.86 by 20 which gives you 3077.2

5 0

3 years ago

Read 2 more answers