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4 years ago

At room temp which of the following is the MOST compressible?

Chemistry

2 answers:

Rom4ik [11]4 years ago

6 0

Answer:

A-one liter of oxygen, a gas

Explanation:

Gas is the most compressible state of matter.

rosijanka [135]4 years ago

5 0

I think the answer is C, Hope I helped you

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The energy of moving electrons is known as?

andrew-mc [135]

The answer is electrical energy

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3 years ago

An object weighing 80 kg floating in a fluid. How does the object's density compared to the density of the fluid

posledela

The object is less then the fluid c

6 0

4 years ago

Read 2 more answers

Calculate the density of a liquid if 58.9 ml of it has a mass of 46.08 g. answer in units of g/ml.

alexira [117]

Density of a solution is mass of solution per unit volume
Density = mass/volume
mass of solution is 46.08 g
volume of solution is 58.9 mL
since mass and volume is known, density can be calculated
density = 46.08 g / 58.9 mL = 0.78 g/mL

8 0

3 years ago

The equation of 3times x is 38

MrMuchimi

Answer is 38/3 or 12.67

3x=38

x=38/3

therefore answer is the one mentioned above

4 0

3 years ago

A calorimeter contains 22.0 mL of water at 14.0 ∘C . When 2.50 g of X (a substance with a molar mass of 82.0 g/mol ) is added, i

Alik [6]

Answer:

The enthalpy change in the the reaction is -47.014 kJ/mol.

Explanation:

$X(s)+H_2O(l)\rightarrow X(aq)$

Volume of water in calorimeter = 22.0 mL

Density of water = 1.00 g/mL

Mass of the water in calorimeter = m

$m=1.00 g/mL\times 22.0 mL=22 g$

Mass of substance X = 2.50 g

Mass of the solution = M = 2.50 g + 22 g = 24.50 g

Heat released during the reaction be Q

Change in temperature =ΔT = 28.0°C - 14.0°C = 14.0°C

Specific heat of the solution is equal to that of water :

c = 4.18J/(g°C)

$Q=Mc\times \Delta T$

$Q=24.50 g\times 4.18 J/g ^oC\times 14.0^oC=1,433.74 J=1.433 kJ$

Heat released during the reaction is equal to the heat absorbed by the water or solution.

Heat released during the reaction =-1.433 kJ

Moles of substance X= $\frac{2.50 g}{82.0 g/mol}=0.03048 mol$

The enthalpy change, ΔH, for this reaction per mole of X:

$\Delta H=\frac{-1.433 kJ}{0.03048 mol}=-47.014 kJ/mol$

5 0

3 years ago