Explanation:
The species or elements which gain electrons and reduces itself are known as oxidizing agent or oxidant.
Ability of an element to act as an oxidizing agent depends on its electrode potential.
The electrode potential of 
is 0.52 V.
The electrode potential of 
is -0.41 V.
The electrode potential of 
is -2.38 V.
Greater is the value of electrode potential, stronger will be the oxidizing agent.
Therefore, rank of these species by their ability to act as an oxidizing agent are as follows.
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Number of photons can be calculated by dividing the needed energy by the energy per photon.
The minimum energy needed is given as 2 x 10^-17 joules
Energy per photon = hc / lambda where h is planck's constant, c is the speed of light and lambda is the wavelength
Energy per photon = (<span>6.626 x 10^-34 x 3 x 10^8) / (475 x 10^-9)
= 4.18 x 10^-19 J
number of photons = (2 x 10^-17) / (4.18 x 10^-19)
= 47.79 photons which is approximately 48 photons</span>
Americium is an element named for a country in the Western Hemisphere
Answer:
a. The temperature and precipitation will both differ.
The reaction for the decomposition of Manganese(II) iodide when exposed to light to form manganese and iodine is MnI2 → Mn + I2.
<h3>THE DECOMPOSITION OF MANGANESE (II) OXIDE:</h3>
- Manganese II iodide has the chemical formula of MnI2. Manganese II iodide can be decomposed in the presence of light to form manganese and iodine.
- The balanced chemical equation of the decomposition is as follows:
MnI2 → Mn + I2
Therefore, the reaction for the decomposition of Manganese(II) iodide when exposed to light to form manganese and iodine is MnI2 → Mn + I2.
Learn more about decomposition at: brainly.com/question/24936069
