Answer:
The mass in grams of N₂O gas that can be dissolved is 0.18 g
Explanation:
The solubility of a gas is proportional to the partial pressure of that gas, over a determined solvent. That's what Henry's law states. We see the formula:
S = K . Pp
Where S is solubility and K is Henry's constant. This specific for each gas and each temperature, while Pp means partial pressure.
We replace data:
S = 0.025 M/atm . 0.69atm
S = 0.01725 M
This is the solubility of the gas, so now, we need to know what mass of gas is solubilized. We convert the moles, with the volume of water.
0.01725 mol/L . 0.235 L = 4.05×10⁻³ moles
Now, we determine the mass in grams: 4.05×10⁻³ mol . 28 g / 1mol =
0.1782 g
The exact molecular mass for butane (C4H10) is
12.0096*4+1.0079*10=58.1174 which is 58.1 to 3 significant figures.
Proportion of carbon in the compound
12.0096*4: 58.1174
=>
48.0384 : 58.1174
The mass of carbon in 2.50 grams of butane can be obtained by proportion, namely
Mass of carbon
= 2.50 * (48.0384/58.1174)
= 2.0664
= 2.07 g (approximated to 3 significant figures)
I'm assuming you need to know the percentage yield of the reaction
To calculate the percentage yield = (actual yield x 100%) / predicted yield
actual yield is 56,9 g
predicted yield is 36,6g ( is the amount that's expected if nothing had got lost)
(56,9 x100)/36,6=
= 155%
Anything carbon in composition