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Anuta_ua [19.1K]
2 years ago
11

If you burn a nut the same size as the cheeseball, would you get the same

Chemistry
1 answer:
tiny-mole [99]2 years ago
4 0

Answer:

No

Explanation:

The number of calories in food differentiate depending on WHAT you are eating not HOW MUCH of it that you are eating.

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Plz I need help is the 2nd time I post this
pychu [463]

Answer:

2--->C

6---->E

3---->D

4--->A

5--->B

1---->F

Explanation:

I think so, sorry if its wrong.

8 0
2 years ago
Which of the following is the quantum number set for an electron in the 3rd energy level, dumb-bell shaped orbital, on the z-axi
Juli2301 [7.4K]

Answer:

Explanation:

Principal quantum no "n" = 3

Azimuthal quantum no "l"= 1

Magnetic quantum no "m"= +1/2

Over all is 3pz

5 0
2 years ago
Calculate the mass in grams of calcium carbonate present in a 50.00 mL sample of an aqueous calcium carbonate standard, assuming
Assoli18 [71]
The units of ppm means parts per million. Also, It is equivalent to milligrams per liter. It is one way of expressing concentration of a substance. It u<span>sually used to describe the concentration of something in water or soil. We calculate the mass of CaCO3 as follows:

Mass = 75 mg/L (.050 L) = <span>3.75 mg CaCO3</span></span>
7 0
3 years ago
Side Show
den301095 [7]

Answer: if you have this app then you’r not smart

Explanation: because cheating is not allowed

4 0
2 years ago
Which choice gives the correct oxidation numbers for all three elements in rb2so3 in the order that the elements are shown in th
vlabodo [156]
<h3>Answer:</h3>

             Rb  =  + 1

              S    =  + 4

              O   =  - 2

<h3>Explanation:</h3>

                   Oxidation states of the elements were calculated keeping in mind the basic rules of assigning oxidation states which included assignment of +1 charge to first group elements i.e. Rubidium (Rb) and assignment of -2 charge to Oxygen atom. Then the oxidation state of Sulfur was calculated as follow,

Rb₂ + S + O₃  =  0

Above zero (0) means that the overall molecule is neutral.

Putting values of Rb and O,

                                           (+1)₂ + S + (-2)₃  =  0

                                           (+2) + S + (-6)  =  0

                                           +2 + S - 6  = 0

                                           S - 6  =  -2

                                          S  =  -2 + 6

                                           S  =  + 4

7 0
3 years ago
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