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2 years ago

If you burn a nut the same size as the cheeseball, would you get the same

Chemistry

1 answer:

tiny-mole [99]2 years ago

4 0

Answer:

Explanation:

The number of calories in food differentiate depending on WHAT you are eating not HOW MUCH of it that you are eating.

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How many grams of nacl are required to make 500.0 ml of a 1.500 m solution?

mestny [16]

<span>43.83g of nacl are required to </span><span>make 500.0 ml of a 1.500 m solution.</span>

4 0

2 years ago

Read 2 more answers

Jimmy mixes 2 chemicals in the lab. The chemicals change color and they get hot. The rise in temperature

gladu [14]

Answer:

A chemical reaction.

Explanation:

A change in temperature is evidence of a chemical reaction.

Also: They are chemicals...

3 0

2 years ago

Convert 90.23 kPa into atm

svlad2 [7]

Answer:

The answer is

Explanation:

To convert from kPa to atm we use the conversion

101.325 kPa = 1 atm

Then

90.23 kPa will be

$\frac{90.23}{101.325} \\ =0.89050086...$

We have the final answer as

Hope this helps you

6 0

3 years ago

A superconductor performs best at??

Charra [1.4K]

very cold temperatures

Explanation:

A superconductor performs best at very cold temperatures.

A superconductor is a perfect conductor that is able to allow the passage of electricity and heat without resistance.

In superconductors, under certain conditions, resistance ceases to exist.
Examples are aluminium, niobium e.t.c
A conductor allows heat and current to pass through but with little resistance.

learn more:

Metals brainly.com/question/2474874

#learnwithBrainly

4 0

2 years ago

What is the empirical formula for a compound that contains 10.89% magnesium 31.77% chloride and 57.34% oxygen

Blizzard [7]

Answer: $Mg_{1}Cl_{2}O_{8}$

Explanation:

If percentage are given then we are taking total mass is 100 grams.So, the mass of each element is equal to the percentage given.

Mass of Mg = 10.89 g

Mass of Cl = 31.77 g

Mass of O = 57.34 g

Step 1 : convert given masses into moles.

Moles of Mg= $\frac {\text{ given mass of Mg}}{\text{ molar mass of Mg}}= \frac {10.89g}{24g/mole}=0.45moles$

Moles of Cl = $\frac {\text{ given mass of Cl}}{\text{ molar mass of Cl}}= \frac {31.77g}{35.5g/mole}=0.89moles$

Moles of O = $\frac {\text{ given mass of O}}{\text{ molar mass of O}}=\frac {57.34g}{16g/mole}=3.58moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Mg = $\frac {0.45}{0.45}=1$

For Cl = $\frac {0.89}{0.45}=2$

For O= $\frac {3.58}{0.45}=8$

The ratio of Mg :Cl : O= 1 : 2 : 8

Hence the empirical formula is $Mg_{1}Cl_{2}O_{8}$

4 0

2 years ago