Step-by-step answer:
The general form of an equation centered at O(0,0) is given by
x^2+y^2=r^2
where r is the radius, (x,y) is any point on the circumference.
If B(4,5) lies on the circumference, then we can find the radius of the circle by substitution:
4^2+5^2=r^2
=>
r^2 = 16+26 =41
Hence the equation of a circle centred at O(0,0) and B(4,5) on its circumference is
x^2 + y^2 = 41
Answer:
Option B
40x + 50y = 130
5x - 4y = 16
Option C
20x + 25y = 65
-20x + 16y = 64
Step-by-step explanation:
we have
----> equation a
----> equation b
we know that
If two system of equations are equivalent, then their solution is the same
Part 1)
step 1
Multiply by 10 equation a both sides

----> equation a'
step 2
Divide by 2 equation b both sides

----> equation b'
so
The system of equations a and b and the system of equations a' and b' are equivalent
therefore
The system of equations a' and b' have the same solution as the given system
Part 2)
step 1
Multiply by 5 equation a both sides

----> equation a'
step 2
Multiply by -2 equation b both sides

----> equation b'
so
The system of equations a and b and the system of equations a' and b' are equivalent
therefore
The system of equations a' and b' have the same solution as the given system
Answer:
see explanation
Step-by-step explanation:
- 2.3 + (- 5.7)
reminder that + (- ) = -
To obtain - 3.4 it is likely that she added 2.3 to - 5.7
The solution is
- 2.3 - 5.7 = - 8
Let x = the number
6x + 12 = 8x
Subtract 6x on both sides of equation.
12 = 2x
Divide both sides of equation by 2.
6 = x
The number is 6.