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Kaylis [27]
3 years ago
14

3.How many grams of lithium nitrate will be needed to

Chemistry
1 answer:
ZanzabumX [31]3 years ago
4 0

Answer:

m_{LiNO_3}=314gLiNO_3

Explanation:

Hello!

In this case, for the given chemical reaction:

Pb(SO_4 )_2, + 4 LiNO_3 \rightarrow Pb(NO_3)_4, + 2 Li_2 SO_4

We can see a 4:2 mole ratio between lithium nitrate (68.946 g/mol) and lithium sulfate (109.94 g/mol); in such a way, via stoichiometry, the required mass of lithium nitrate to make 250 g of lithium sulfate turns out:

m_{LiNO_3}=250gLi_2SO_4*\frac{1molLi_2SO_4}{109.94gLi_2SO_4} *\frac{4molLiNO_3}{2molLi_2SO_4} *\frac{68.946gLiNO_3}{1molLiNO_3}\\\\m_{LiNO_3}=314gLiNO_3

Best regards!

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The question is missing the table. Here is the complete question.

The tableshows the concentration of a reactant in the mixture over a period of time.

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Average = \frac{1}{450}

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