Answer:
1.5
Explanation:
Given that :
Compound A and B are formed from Sulfur + Oxygen.
Compound A :
6g sulfur + 5.99g Oxygen
Compound B:
8.6g sulfur + 12.88g oxygen
Comparing the ratios :
Compound A:
S : O = 6.00 : 5.99
S/0 = 6.0g S / 5.99g O
Compound B :
S : O = 8.60 : 12.88
S / O = 8.60g S / 12.88g O
Mass Ratio of A / mass Ratio of B
(6.0g S / 5.99g O) ÷ (8.60g S / 12.88g O)
(6.0 g S / 5.99g O) × (12.88g O / 8.60g S)
(6 × 12.88) / (5.99 × 8.60)
= 77.28 / 51.514
= 1.50017
= 1.5
HNO3 and H2SO4 are Arrhenius acids which will increase the concentration of H+ when dissolved in water.
KOH and Ca(OH)2 are Arrhenius bases that increase the concentration of OH- when dissociated in water.
1) 1 nm = 0.001 µm; one nanometer is equal to 0.001 (10⁻³) micrometer.
d(H) = 10 nm; diameter of hydrogen atom.
d(H) = 10 nm · 0.001 µm/nm.
d(H) = 0.01 µm = 10⁻² µm.
2) 1 nm = 10⁻⁹ m
; one meter is equal to 0.0000000001 (10⁻⁹) meter.
d(H) = 10 nm.
d(H) = 10 nm · 10⁻⁹ m/nm.
d(H) = 0.00000001 m = 10⁻⁸ m.
3) 1 nm = 10⁻⁶ mm
; one nanometer is equal to 0.000001 (10⁻⁶) millimeter.
d(H) = 10 nm · 10⁻⁶ mm/nm.
d(H) = 0.00001 mm = 10⁻⁵ mm.
