Answer:
7 mm per year
Explanation:
It is given that :
The Pacific plate is moving towards north at = 29 mm per year
The Pacific plate is moving towards west at = 20 mm per year
We have to calculate the total relative motion towards the northwest.
So we have to find the resultant of the two motions.
Since the two movements are perpendicular, therefore the angle between the two motions is 90 degree.
Therefore, finding their resultant,


R = 7
Therefore, total relative motion towards the northwest is 7 mm per year.
Answer:

Explanation:
Hello.
In this case, for this uniformly accelerated motion in which the car starts from rest at 0 m/s and travels 18 m in 3.0 s, we can compute the acceleration by using the following equation:

Whereas the final distance is 18 m, the initial distance is 0 m, the initial velocity is 0 m/s and the time is 3.0 s, that is why the acceleration turns out:

Best regards.
Answer:
Explanation:
Length, l = 4.32 x 10^4 m
speed, v = 7.07 x 10^3 m/s
magnetic field, B = 5.81 x 10^-5 T
The formula for the motion emf is given by
e = B x v x l
e = 5.81 x 10^-5 x 7.07 x 10^3 x 4.32 x 10^4
e = 17745.1 V
Answer:
x = 11.23 m
Explanation:
For this interesting exercise, we must use angular kinematics, linear kinematics and the relationship between angular and linear quantities.
Let's reduce to SI system units
θ = 155 rev (2pi rad / rev) = 310π rad
α = 2.00rev / s2 (2pi rad / 1 rev) = 4π rad / s²
Let's look for the angular velocity at the time the piece is released, with starting from rest the initial angular velocity is zero (wo = 0)
w² = w₀² + 2 α θ
w =√ 2 α θ
w = √(2 4pi 310pi)
w = 156.45 rad / s
The relationship between angular and linear velocity
v = w r
v = 156.45 0.175
v = 27.38 m / s
In this part we have the linear speed and the height that it travels to reach the floor, so with the projectile launch equations we can find the time it takes to arrive
y =
t - ½ g t²
As it leaves the highest point its speed is horizontal
y = 0 - ½ g t²
t = √ (-2y / g)
t = √ (-2 (-0.820) /9.8)
t = 0.41 s
With this time we calculate the horizontal distance, because the constant horizontal speed
x = vox t
x = 27.38 0.41
x = 11.23 m