Would a larger balloon float better or worse than a smaller balloon?

Physics

1 answer:

CaHeK987 [17]1 year ago

4 0

Answer:

The bigger balloon will have a larger area and would experience a greater buoyant force exerted on it which would make it even lighter than a smaller balloon and will have higher payload capacity than a smaller one.

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an electric current of 285.0 ma flows 674. milliseconds. Calculate the amount of electric charge transported. Be sure your answe

yulyashka [42]

Answer:

The amount of electric charge transported = 0.192 C

Explanation:

Electric Charge: This is defined as the product of electric current and time in an electric circuit, The S.I unit of electric charge is Coulombs (C)

Q = It..................... Equation 1

Where Q = Electric charge, I = electric current, t = time.

Given: I = 285 mA, t = 674 milliseconds.

Conversion: (i) Convert from 285 mA to A = (285/1000) A = 0.285 A

(ii) convert from 674 milliseconds to seconds = (674/1000) s = 0.674 s

Substituting these values into equation 1

Q = 0.285 × 0.674

Q = 0.192 C

Therefore the amount of electric charge transported = 0.192 C

5 0

2 years ago

An uncrewed mission to the nearest star, Proxima Centauri, is launched from the Earth's surface as a projectile with an initial

Anna [14]

Answer:

42.96 km/s

Explanation:

From the conservation of Energy

$(PE+KE)_i=(PE+KE)_f\\\Rightarrow -\frac{GmM}{R}+\frac{1}{2}mv_i^2=0+\frac{1}{2}mv_f^2$

Mass gets cancelled

$-\frac{GM}{R}+\frac{1}{2}v_i^2=0+\frac{1}{2}v_f^2\\\Rightarrow -2\frac{GM}{R}+v_i^2=v_f^2\\\Rightarrow -v_e^2+v_i^2=v_f^2\\\Rightarrow v_f=\sqrt{v_i^2-v_e^2}$