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fredd [130]
3 years ago
12

Which method would determine the volume of prism with dimesions 2×21/4×4 shown below?​

Mathematics
1 answer:
snow_tiger [21]3 years ago
6 0

Answer:

42

Step-by-step explanation:

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A certain building has a triangular shaped face to link up of the sides of the triangular base or 145 feet 257 feet in 290 feet
attashe74 [19]

Answer:

18617.66 ft^2

Step-by-step explanation:

sides of triangular base

a=  145ft  ,

b = 257ft ,

c =  290ft

<u>calculate the area of the base  </u>

The base is a scalene triangle hence the area is calculated as follows

s = ( a + b + c ) / 2

  = ( 145 + 257 + 290 ) / 2 = 346

Area of triangle = \sqrt{s(s-a)(s-b)(s-c)}  = \sqrt{346(201)(89)(56)}

                          = 18617.66 ft^2

3 0
3 years ago
Please help me! ASAP!!!!!
Greeley [361]

Answer:

x=36

Step-by-step explanation:

17+3 =20

now we have :

x+4

___         = 20

  2

20*2= 40

x+4=40

x=36

hopes this helps

4 0
3 years ago
Need help<br> x-17/3=-3 <br> Have a great day
bogdanovich [222]

Answer:

x=8

Step-by-step explanation:

6 0
3 years ago
(MATH) (6) ((PHOTO))<br>label is sq yd​
Annette [7]

Answer:

<em>20 sq yd</em>

Step-by-step explanation:

To find the total amount of sq yd's of paint needed, you have to find the area.

The area of a triangle is: A = 1/2 bh

We know:

b = base = 8

h = height = 5

Plug in and solve:

A = 1/2 (8) (5)

A = 1/2 (40)

A = 20

5 0
3 years ago
A homeowner has an octagonal gazebo inside a circular area. Each vertex of the gazebo lies on the circumference of the circular
Tcecarenko [31]

If we draw the diagonals of the octagonal gazebo, the 4 diagonals divide the octagon into 8 triangles.

Note that each triangle is an isosceles triangle whose equal sides are x, the radius of the circle.

The top angle of each triangle is obtained by dividing the full angle by 8.

So, each top angle = \frac{360}{8}

= 45°

Now, in fig., consider one of the triangles Δ OAB. Draw an altitude OC from O to the opposite side AB.

This altitude OC bisects the top angle 45°.

Therefore, ∠ AOC = 22.5°.

Now, in Δ AOC,

sin 22.5=\frac{AC}{OA}

=\frac{AC}{x}

So, AC = x sin 22.5°

Note that, AB = 2 AC.

Therefore, AB = 2x sin 22.5°.

Also, cos 22.5=\frac{OC}{OA}

=\frac{OC}{x}

So, OC = x cos 22.5°.

Area of Δ AOB = \frac{1}{2}(AB)(OC)

= \frac{1}{2} × (2x sin 22.5°) × (x cos 22.5°)

= \frac{1}{2} x^{2} (2 sin 22.5° cos 22.5°)

= \frac{1}{2} x^{2} sin 45°

= x^{2} / 2\sqrt{2}

Area of the octagonal gazebo = 8 × one triangular area

= 8 × (x^{2} / 2\sqrt{2})

=2\sqrt{2} x^{2}

=2.828x^{2}

Area required for mulch = circular area - area of the gazebo

=3.14x^{2} -2.828x^{2}

=0.312x^{2}

Now, cost per unit area = $1.50.

Hence, total cost g(m) = area × cost per unit area

Total cost g(m) = 0.312x^{2} × 1.5

=0.468x^{2}

Hence, total cost g(m) = 0.468x^{2}.

4 0
3 years ago
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