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Illusion [34]
3 years ago
10

[Q61 Assume X is normally distributed with a mean of 10 and a variance of 4. Determine the following: (a) (b) (c) (d) < 13) P

(X > 9) < x < 14) Determine the value of x such that P(-x < X— 10 < x) — 0 99
Mathematics
1 answer:
Lady bird [3.3K]3 years ago
8 0

Answer:

6325

Step-by-step explanation:

do the math vddddddddd

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Find the difference (7a-6b+7) - (8a-2)
olga nikolaevna [1]
Hey there!

Let's set up our expression:

(7a-6b+7)-(8a-2)

In order to simplify, we can use that subtraction sign and distribute it, using the distributive property. We have:

7a-6b+7-8a+2

Notice how it's plus two, because a negative times a negative two is a positive two. Now, it's a matter of finding the like terms and adding or subtracting them. These like terms can either have no variable, or have different coefficients but the same variable. That means our like terms are the 7a and -8a, and the 7 and 2. There's no like term for the 6b. That means we have:

(7a-8a) - 6b + (7+2) =

-a - 6b + 9

Hope this helps!
6 0
3 years ago
In a bowl of marbles, there are 10 red ones, 6 blue ones, and green onesa marble is chosen at random from the bowl, find P(red o
Zolol [24]

Answer:

It is most-likely a red marble

Step-by-step explanation:

I say it is a red marble because as you said, there are 10 red marbles and 6 blue ones and since there are 4 more red marbles, there is a higher perchentage of it being a red marble . (I hope i answered your question)

6 0
3 years ago
Read the excerpt from Immigrant Kids, and then answer the question.
pogonyaev

Answer:

Its A

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Rose has 5 times as many stickers as John. They have 300 stickers in all. How many more stickers does Rose have than John? Show
kirill115 [55]

5x+x=300

6x=300

x=50

5(50)=250 (Rose)

x=50(John)

Rose has 250 stickers and John has 50, therefore Rose has 200 more stickers than John.

6 0
3 years ago
Read 2 more answers
A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex
Roman55 [17]

Answer:

 Standard error (S.E) =  0.048  ≅ 0.05

Step-by-step explanation:

<u>Explanation</u>:-

Given  sample size 'n'=76

Given the dean who randomly selects 76 students and finds that 58 out of 76 are receiving financial aid.

Sample proportion

                         p = \frac{x}{n} = \frac{58}{76} = 0.7631

The standard error is determined by

                     S.E = \sqrt{\frac{p(1-p)}{n} }

                     S.E = \sqrt{\frac{0.763(0.2369}{76} }

  Standard error is 0.048  ≅ 0.05

3 0
3 years ago
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