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3 years ago

Synthetic division (3x^2 - 4 + x^3) = (x - 1)

Mathematics

1 answer:

PolarNik [594]3 years ago

6 0

Answer:

x³+3x²-4/×-1=x²+4x+4+0/x-1=x²+4x+4

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what is the median of-16 -20 -23 10 -1 10 -1 0 0 -10 7 11 17 22 15 19 16 17 35 29 17 19 22 16 24 25 17 25

yawa3891 [41]

Answer:

Step-by-step explanation:

-23, -20, -16, -10, -1, -1, 0, 0, 7, 10, 10, 11, 15, 16, 16, 17, 17, 17, 17, 19, 19, 22, 22, 24, 25, 25, 29, 35

3 0

3 years ago

PLEASE HELP ASAP WILL GIVE BRAINLIEST + 99 POINTS!! What is the area of this figure?

NeX [460]

Answer:

a= 81m^2

Step-by-step explanation:

we know the top triangle: the base is 9

a = 1/2(bh)

a = 1/2 (9 x 8)

a = 1/2 (72)

a = 36

the parallelogram at the bottom has base 9 and height 5

a = bh

a = 9 x 5

a = 45

add them together 36 + 45 = 81

7 0

3 years ago

Read 2 more answers

In a class of 42 students the number of boys is 2/5 of the girls . find the number of boys and girls

Ksju [112]

In plain and short, we simply divide 42 by (2+5) and distribute accordingly.

$\bf \cfrac{boys}{girls}\qquad 2:5\qquad \cfrac{2\cdot \frac{42}{2+5}}{5\cdot \frac{42}{2+5}}\implies \cfrac{2\cdot 6}{5\cdot 6}\implies \cfrac{12}{30}$

3 0

3 years ago

The school production of Our Town' was a big success. For opening night. 434 tickets were sold. Students paid $4.00 each, while

Alex73 [517]

Answer:

286 students attended

148 non students attended

Step-by-step explanation:

Given

$Tickets = 434$

$Students = \$4.00$

$Non-Students = \$6.00$

$Total = \$2032.00$

Solving (a): Number of students

Represent students with S and non students with N

So:

$S + N = 434$ --- (1)

$4S + 6N = 2032$ --- (2)

Make N the subject of formula in (1)

$N = 434 - S$

Substitute 434 - S for N in (2)

$4S +6(434 - S) = 2032$

Open Bracket

$4S + 2604 - 6S = 2032$

Collect Like Terms

$4S - 6S = 2032 - 2604$

$-2S = -572$

Divide through by -2

$S = 286$

<em>Hence; 286 students attended</em>

Solving (b):

Recall that

$N = 434 - S$

$N = 434 - 286$

$N = 148$

<em>148 non students attended</em>

4 0

3 years ago

An athletics coach states that the distribution of player run times (in seconds) for a 100-meter dash is normally distributed wi

Fofino [41]

Answer:

6.68%

Step-by-step explanation:

First find the z-score:

z = (x − μ) / σ

z = (13.30 − 13.00) / 0.2

z = 1.50

Look the value up in a z-score table, or use a calculator.

P(z>1.50) = 1 − 0.9332

P(z>1.50) = 0.0668

6.68% of players on the team run the 100 meter dash in 13.30 seconds or faster.

3 0

4 years ago