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1 year ago

13

A closed system:

1 answer:

adoni [48]1 year ago

3 0

The answer is b i just did the test

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What causes atoms to bond together<br> ?!?

lisov135 [29]

Answer:

electrostatic attraction

Explanation:

Atoms form chemical bonds with other atoms when there's an electrostatic attraction between them. This attraction results from the properties and characteristics of the atoms' outermost electrons, which are known as valence electrons.

7 0

3 years ago

Read 2 more answers

Which statement best describes the atoms of the gas neon?

Leya [2.2K]

Answer:

They:

-Are far from each others

-Move constantly

-Move freely (all directions)

-Move at high speed

5 0

2 years ago

How do you find the water pressure at the bottom of the 55-m-high water tower?

svp [43]

-- What's the volume of a cylinder with radius=1m and height=55m ?

   ( Volume of a cylinder = π R² h )

-- How much does that volume of water weigh ?

    1 liter of water = 1 kilogram of mass
Weight = (mass) x (acceleration of gravity)

-- What's the area of the bottom of that 1m-radius cylinder ?

   Pressure = (force) / (area)

5 0

2 years ago

If you lift weights faster than normal you have increased what?

egoroff_w [7]

I belive it would power I’m not 100% sure. If it’s not power then force

8 0

2 years ago

A piston-cylinder device contains Helium gas initially at 150 kPa, 20 o C, and 0.5m 3 . The helium is now compressed in a polytr

Molodets [167]

Answer:

Explanation:

Given

$P_1=150 kPa$

$T_1=20^{\circ}C$

$V_1=0.5 m^3$

$T_2=140^{\circ}C$

$P_2=400 kPa$

R for Helium $R=2.076$

$c_v=3.115 kJ/kg-K$

mass of gas $m=\frac{P_1V_1}{RT_1}$

$m=\frac{150\times 0.5}{2.076\times 293}$

$m=0.123 kg$

Similarly $V_2$ can be found

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

$V_2=0.264 m^3$

Work done $W=\int_{V_1}^{V_2}PdV$

$W=\frac{P_2V_2-P_1V_1}{n-1}$

$W=\frac{mR(T_2_T_1)}{n-1}$

Since it is a polytropic Process

therefore $PV^n=c$

$P_1V_1^n=P_2V_2^n$

$(\frac{V_1}{V_2})^n=\frac{P_2}{P_1}$

$(\frac{0.5}{0.264})^n=\frac{400}{150}$

$n=\frac{\ln 2.66}{\ln 1.893}$

$n=1.533$

$W=\frac{0.123\times 2.076(140-20)}{1.533-1}$

$W=57.48 kJ$

From Energy balance

$E_{in}-E_{out}=\Delta E_{system}$

Neglecting kinetic and Potential Energy change

$Q_{in}+W_{in}=change\ in\ Internal\ Energy$

Change in Internal Energy $\Delta U=u_2-u_1$

$\Delta U=mc_v(T_2-T_1)$

$\Delta U=0.123\times 3.115(140-20)$

$\Delta U=45.977 kJ$

$Q_{in}+57.48=45.977$

$Q_{in}=-11.50 kJ$

i.e. Heat is being removed

3 0

3 years ago