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frez [133]
2 years ago
13

A closed system:

Physics
1 answer:
adoni [48]2 years ago
3 0
The answer is b i just did the test
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Which would hit the ground first if dropped from the same height in a vacuum—a feather or a metal bolt?
vovikov84 [41]
They hit the ground at the same time
4 0
3 years ago
A racing car can complete an 800 m long lap in 14 s. What is the speed of the<br> car?
nasty-shy [4]

Answer:

57.1 m/s

Explanation:

Speed = Distance/Time

Speed = 800/14

Speed = 57.1 m/s (3sf)

7 0
3 years ago
A 65.0-kg woman steps off a 10.0-m diving platform and drops straight down into the water. 1) If she reaches a depth of 3.40 m,
babymother [125]

Answer:

19372.29 N

Explanation:

Kinetic Energy of the man = Work done by the average resistive force of water.

mg(H+d) = F×d............................ Equation 1

where, m = mass of the woman, H = Height of the platform, d = depth of water reached, F = average resistive force exerted by water.

make F the subject of the equation,

F = mg(H+d)/d...................... Equation 2

Given: m = 65.0 kg, H = 10 m, d = 3.4 m, g = 9.8 m/s²

Substitute into equation 2

F = 65(9.8)(100+3.4)/3.4

F = 19372.29 N

8 0
3 years ago
What pressure is transmitted to the wheel cylinder if 200N is applied on the brake pedal of master cylinder with a radius of 12c
Semmy [17]

Answer:

pressure = force/area

force = 200N

area = πr², π =3.142, r = 12 cm = 0.12 m

pressure = 200/3.142×(0.12)²

p = 200/3.142×0.24

p = 200/0.754

p = 265.25 Nm-¹ or 265.25 Pa

5 0
3 years ago
A conveyor belt is used to send burgers through a grill- ing machine. If the grilling machine is 1.2m long and the burgers requi
puteri [66]

Answer:

Rate = 1.71 burger/min

Explanation:

Length of the conveyor belt is given as

L = 1.2 m

time taken to cook one burger is given as

t = 2.8 min = 168 s

now we can find the speed of the belt as

v = \frac{distance}{speed}

v = \frac{1.2}{168}

v = 7.14 \times 10^{-3} m/s

Now we know that the distance between two burgers is given as 25 cm

d = 0.25 m/burger

now the production rate of burgers is given as

Rate = \frac{v}{d}

Rate = \frac{7.14 \times 10^{-3} m/s}{0.25 m/burger}

Rate = 0.0286\frac{burger}{sec}

Rate = 0.0286\times 60\frac{burger}{min}

Rate = 1.71 burger/min

8 0
3 years ago
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