Answer:
2,4
Explanation:
LOL WHERE THE PICTURE GURL?
Answer
given,
v = 128 ft/s
angle made with horizontal = 30°
now,
horizontal component of velocity
vx = v cos θ = 128 x cos 30° = 110.85 ft/s
vertical component of velocity
vy = v sin θ = 128 x sin 30° = 64 m/s
time taken to strike the ground
using equation of motion
v = u + at
0 =-64 -32 x t
t = 2 s
total time of flight is equal to
T = 2 t = 2 x 2 = 4 s
b) maximum height
using equation of motion
v² = u² + 2 a h
0 = 64² - 2 x 32 x h
64 h = 64²
h = 64 ft
c) range
R = v_x × time of flight
R = 110.85 × 4
R = 443.4 ft
42- C
43- A
44- C
45- A
46- B
47- D
Answer:
9064.44 Nm
Explanation:
Since the steel is uniform, the center of mass is also at the geometric center, which is 3.5 / 2 = 1.75 m from the bolted point.
Let g = 9.81 m/s2. The weight of the beam and the worker is
So the total torque about the bolted point is the sum of product of weights and distances from weight to the bolted point
