A 1.60-m-long barbell has a 25.0 kg weight on its left end and a 37.0 kg weight on its right end. you may want to review ( pages
204 - 205) . part a if you ignore the weight of the bar itself, how far from the left end of the barbell is the center of gravity
1 answer:
Refer to the diagram shown below.
The weight at the left end is
W₁ = (25.0 kg)*(9.8 m/s²) = 245 N
The weight at the right end is
W₂ = (37.0 kg)*(9.8 m/s²) = 362.6 N
The reaction at the fulcrum is
R = W₁ + W₂
Let x = distance of the fulcrum (c.g.) from the left end.
For equilibrium, take moments about the center of gravity (c.g).
(245 N)*(x m) - (362.6 N)*(1.6-x m) = 0
245x - 580.16 + 362.6x = 0
607.6x = 580.16
x = 0.955 m
Answer: 0.955 m
The weight at the left end is
W₁ = (25.0 kg)*(9.8 m/s²) = 245 N
The weight at the right end is
W₂ = (37.0 kg)*(9.8 m/s²) = 362.6 N
The reaction at the fulcrum is
R = W₁ + W₂
Let x = distance of the fulcrum (c.g.) from the left end.
For equilibrium, take moments about the center of gravity (c.g).
(245 N)*(x m) - (362.6 N)*(1.6-x m) = 0
245x - 580.16 + 362.6x = 0
607.6x = 580.16
x = 0.955 m
Answer: 0.955 m
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