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Colt1911 [192]
3 years ago
5

A 1.60-m-long barbell has a 25.0 kg weight on its left end and a 37.0 kg weight on its right end. you may want to review ( pages

204 - 205) . part a if you ignore the weight of the bar itself, how far from the left end of the barbell is the center of gravity

Physics
1 answer:
oksian1 [2.3K]3 years ago
5 0
Refer to the diagram shown below.

The weight at the left end is
W₁ = (25.0 kg)*(9.8 m/s²) = 245 N
The weight at the right end is
W₂ = (37.0 kg)*(9.8 m/s²) = 362.6 N
The reaction at the fulcrum is
R = W₁ + W₂

Let x =  distance of the fulcrum (c.g.) from the left end.
For equilibrium, take moments about the center of gravity (c.g).
(245 N)*(x m) - (362.6 N)*(1.6-x m) = 0
245x - 580.16 + 362.6x = 0
607.6x = 580.16
x = 0.955 m

Answer: 0.955 m

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