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HACTEHA [7]
3 years ago
8

The Astronomer Carl Sagan is famous. Why?

Physics
1 answer:
Zolol [24]3 years ago
6 0
Mainly because he was Johnny Carson's advisor and consultant
on space, astronomy, and science in general, and he appeared
on The Tonight Show Starring Johnny Carson many times.
You might be interested in
Which evidence is lost likely used to indicate the beginning of solar system formation?
deff fn [24]

Explanation :

Our solar system was formed about 4.6 billion years ago. It is formed when gravity exerted low-density cloud of interstellar gas and dust. The massive cloud of gas and dust is called as Orion Nebula.  

In a small area, the overdensity of clouds occurs. This caused the contraction, to begin. Due to this contraction the potential energy gets converted into kinetic energy of individual gas particles.

Hence the correct option is " materials were pulled together by the gravity". This is the one of the evidence used to indicate the beginning of the solar system.  

7 0
3 years ago
The answer is not B.
mezya [45]

Answer:

D

Explanation:

15m/ s

i hope this helps

4 0
2 years ago
XERCISE
kkurt [141]

The answer is Anguer...

<em>Hope </em><em>it </em><em>helps.</em><em>.</em><em>.</em><em> </em><em>pls </em><em>mark</em><em> brainliest</em>

3 0
3 years ago
Landslides and mudslides can result from both volcanoes and earthquakes.<br><br> true<br> false
EleoNora [17]
The correct answer would be True!
4 0
4 years ago
A body is thrown up with a velocity of 78.4 m per second.How high will it rise and how much time it will take to return to its p
a_sh-v [17]

Answer:

The maximum height reached by the body is 313.6 m

The time to return to its point of projection is 8 s.

Explanation:

Given;

initial velocity of the body, u = 78.4 m/s

at maximum height (h) the final velocity of the body (v) = 0

The following equation is applied to determine the maximum height reached by the body;

v² = u² - 2gh

0 = u² - 2gh

2gh = u²

h = u²/2g

h = (78.4²) / (2 x 9.8)

h = 313.6 m

The time to return to its point of projection is calculated as follows;

at maximum height, the final velocity becomes the initial velocity = 0

h = v + ¹/₂gt²

h = 0 + ¹/₂gt²

h =  ¹/₂gt²

2h = gt²

t² = 2h/g

t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 313.6}{9.8} }\\\\t = 8 \ s

4 0
3 years ago
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