Explanation:
Given that,
Displacement in ice block, 
Force exerted by water, 
To find,
Work done by the force during the displacement.
Solve,
We know that the product of force and displacement is called work done. It is also equal to the dot product of force and displacement as :
We know that, i.i = j.j = k.k = 1
So, the work done by the force on the block during the displacement is 4181 Joules.
Answer:
18.9 <em>N or </em><em>19</em><em> N </em>rounded
Explanation:
m = 0.145 kg
a = 130 m/s^2
F = ma = (0.145 kg)(130 m/s^2) = 18.9 <em>N</em>
<h2>The different forces acting on the ball while its in air</h2>
Amy throws a softball through the air. Applied, drag and gravitational forces are acting on the ball while it’s in the air. The softball experiences force as a result of Amy’s throw. As the ball moves, it experiences from the air it passes through.
It also experiences a downward pull because earth has the property to attract everything which is on the earth towards it. The ball is moving in the air but earth applies force on the ball to get back on the ground. Hence, in this way, gravitational force applies.
There is also a drag force which results due to friction that is present in the air. It resist to move ball in the air and there will also be applied force which is given by a person who throws by applying force.
Answer:
add 44m/s and 22m/s then multiply it by 11
Explanation:
Answer:
the distance in meters traveled by a point outside the rim is 157.1 m
Explanation:
Given;
radius of the disk, r = 50 cm = 0.5 m
angular speed of the disk, ω = 100 rpm
time of motion, t = 30 s
The distance in meters traveled by a point outside the rim is calculated as follows;
Therefore, the distance in meters traveled by a point outside the rim is 157.1 m
