Standard sea level pressure by definition equals 760 mm (29.92 inches) of mercury
Answer:
The avarage power of the body is 96.898 watts.
Explanation:
We must notice that given definition of power implies a constant consumption of energy, so that we should assume that energy consumption is constant. A Calorie is equal to 4186 joules. If we know that 
and 
, the power of body, measured in watts, is:
The avarage power of the body is 96.898 watts.
Answer:
a = 1.152s
b = 0.817 m
c = 7.29m/s
Explanation: let the following
From the first equation of linear motion
V = u+at..........1
parameters be represented as :
t = Time taken
v = Final velocity
a = Acceleration due to gravity = 9.8m/s²
u = Initial velocity = 4 m/s
s = Displacement
V = 0
Substitute the values into equation 1
0 = 4-9.8(t)
-4 = -9.8t
t = 4/9.8
t = 0.408s
From : s = ut+1/2at^2.........2
S = 4×0.408+0.5(-9.8)×0.408^2
S= 1.632-4.9(0.166)
S = 1.632-0.815
S = 0.817m
Her highest height above the board is 0.817 m
Total height she would fall is 0.817+1.90 = 2.717 m
From equation 2
s = ut+1/2at^2
2.717 m = 0t+0.5(9.8)t^2
2.717 m = 0+4.9t^2
2.717 m = 4.9t^2
2.717/4.9 = t^2
0.554 =t^2
t =√0.554
t = 0.744s
Hence, her feet were in the air for 0.744+0.408seconds
= 1.152s
Also recall from equation 1
V= u+at
V = 0+9.8(0.744)
V = 7.29m/s
Hence, the velocity when she hits the water is 7.29m/s
Finally,
a = 1.152s
b = 0.817 m
c = 7.29m/s
The term that describes the direction closest to the point of origin is Proximal. Dorsal is the directional term for the movement toward the back of the body. Cephalic is the term that describes the movement towards the top of the body. Ventral on the other hand describes the movement toward the front of the body.
To solve this problem we will apply the energy conservation theorem for which the work applied on a body must be equivalent to the kinetic energy of this (or vice versa) therefore
Here,
m = mass
= Velocity (Final and initial)
First case) When the particle goes from 10m/s to 20m/s
Second case) When the particle goes from 20m/s to 30m/s
As the mass of the particle is the same, we conclude that more energy is required in the second case than in the first, therefore the correct answer is A.
