if its diameter is 6, then its radius is half that or 3.
![\textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h }{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=3\\ h=4 \end{cases}\implies V=\cfrac{\pi (3)^2(4)}{3}\implies V=12\pi \\\\[-0.35em] ~\dotfill\\\\ \textit{surface area of a cone}\\\\ SA=\pi r\sqrt{r^2+h^2}+\pi r^2\qquad \implies \qquad SA=\pi (3)\sqrt{3^2+4^2}+\pi (3)^2 \\\\\\ 3\pi \sqrt{25}+9\pi \implies 3\pi (5)+9\pi \implies 15\pi +9\pi \implies 24\pi](https://tex.z-dn.net/?f=%5Ctextit%7Bvolume%20of%20a%20cone%7D%5C%5C%5C%5C%20V%3D%5Ccfrac%7B%5Cpi%20r%5E2%20h%20%7D%7B3%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D3%5C%5C%20h%3D4%20%5Cend%7Bcases%7D%5Cimplies%20V%3D%5Ccfrac%7B%5Cpi%20%283%29%5E2%284%29%7D%7B3%7D%5Cimplies%20V%3D12%5Cpi%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ctextit%7Bsurface%20area%20of%20a%20cone%7D%5C%5C%5C%5C%20SA%3D%5Cpi%20r%5Csqrt%7Br%5E2%2Bh%5E2%7D%2B%5Cpi%20r%5E2%5Cqquad%20%5Cimplies%20%5Cqquad%20SA%3D%5Cpi%20%283%29%5Csqrt%7B3%5E2%2B4%5E2%7D%2B%5Cpi%20%283%29%5E2%20%5C%5C%5C%5C%5C%5C%203%5Cpi%20%5Csqrt%7B25%7D%2B9%5Cpi%20%5Cimplies%203%5Cpi%20%285%29%2B9%5Cpi%20%5Cimplies%2015%5Cpi%20%2B9%5Cpi%20%5Cimplies%2024%5Cpi)
1 and 3/4 as an improper fraction: 7/4
1/2*7/4=7/8
He should use 7/8 of a cup of sugar.
Answer:
b
Step-by-step explanation:
Total number of plants is 74
Bilennial + perennials = 63
63 is 85% or 74
Answer:
S(1,2)
Step-by-step explanation:
The value that is being altered is the y value if you go from Q to T and then T to S. The x value = 1 and remains the same for point S.
To go from Q to T, you go from 8 to 5 on the y value. Remember x remains the same. That's three units (8 - 5 = 3)
To go from T to S must be 3 units as well, since the small diagonal is bisected. 5 - 3 = 2 is the answer.
So point S is noted as S(1,2)
