1. 29.16
2. 3.5
3. a=0.32
4. 2/15
5. d= 23.33333333 ( am assuming this is a repeating decimal)
The equation is y = 1/8x + 7
Standard form equation is Ax + By = C, where A > = 0.
First eliminate the fractions by multiplying the equation by 8
8y = x + 56
Subtract x from each side
-x + 8y = 56
SInce x coeficient can't be negative multiply the equation by negative one.
<span>x - 8y = -56</span>
f(h(x))= 2x -21
Step-by-step explanation:
f(x)= x^3 - 6
h(x)=\sqrt[3]{2x-15}
WE need to find f(h(x)), use composition of functions
Plug in h(x)
f(h(x))=f(\sqrt[3]{2x-15})
Now we plug in f(x) in f(x)
f(h(x))=f(\sqrt[3]{2x-15})=(\sqrt[3]{2x-15})^3 - 6
cube and cube root will get cancelled
f(h(x))= 2x-15 -6= 2 x-21
wait i think i did the wrong one brb
Answer:
The temperature needs to decrease 71° - 50° = 21° that at least not greater than 50°F
As we know, the device decrease the temperature down 3.5° every hour, so
21 : 3.5 = 6 hour
Call x is the hours we need to wait to let the device decrease, we have
x > 6
Given:
It is given that,
PQ ⊥ PS and
∠QPR = 7x-9
∠RPS = 4x+22
To find the value of ∠QPR.
Formula
As per the given problem PR lies between PQ and PS,
So,
∠QPR+∠RPS = 90°
Now,
Putting the values of ∠RPS and ∠QPR we get,
or, 
or, 
or, 
or, 
Substituting the value of in ∠QPR we get,
∠QPR = 
or, ∠QPR = 
Hence,
The value of ∠QPR is 40°.
