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Maslowich
4 years ago
7

The energy available to primary consumers in an energy pyramid is 800 kilocalories. Approximately how much energy is used by the

primary consumers for their physical functions?
A. Less than 720 kilocalories
B. 720 kilocalories
C. 880 kilocalories
D. More than 880 kilocalories
Chemistry
2 answers:
ki77a [65]4 years ago
5 0
The answer is B, Let me know if you get it right!
torisob [31]4 years ago
3 0

Answer:

B. 720 kilocalories

Explanation:

The primary consumers use about 90% of available energy pyramid for their physical functions. In order to solve this exercise, we need to calculate the 90% of 800 kilocalories.

We can state that there is  a direct linear relationship between the kilocalories and the percentage. This means that for a higher percentage the amount of kilocalories will be greater.

We can write :

\frac{800kilocalories}{100}=\frac{x}{90}

Where the denominators are percentages.

Solving for x :

x=\frac{(800kilocalories).(90)}{100}

x=720kilocalories

The correct option is B. 720 kilocalories

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3 years ago
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Answer:

<u>One lone-Pair is present in Ammonia</u>

<u></u>

Explanation:

The number of valence electron in N = 5

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The formula of ammonia = NH3

Total valence electron in ammonia molecule = 5 +3(1) = 5+3 = 8

The lewis structure suggest that :

Nitrogen completes its octet by sharing the electron pair with 3 hydrogen atoms.

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So,<u><em> remaining two electron are left non-bonded</em></u> . Hence they exist as lone- pair

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5 0
4 years ago
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marusya05 [52]

Answer:

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5 0
3 years ago
Find the force of gravity of 1000 kg car.
ANEK [815]

Answer:

The force of gravity acting on the car is <u>9800 N vertically downward.</u>

Explanation:

Given:

Mass of the car given is 1000 kg.

We know that the force of gravity is the force applied by the center of Earth on any body. The force of gravity is also called the weight of the body and always act towards the center of the Earth.

From Newton's second law, we know that the force acting on a body is equal to its mass and acceleration.

Here, the acceleration acting on the car is due to gravity and thus has a constant value of 9.8 m/s² on the surface of Earth.

Therefore, the force of gravity acting on the car is given using the Newton's second law as:

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Force of gravity = (1000 kg) \times (9.8 m/s²)

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Therefore, the force of gravity acting on the car is 9800 N vertically downward.

6 0
3 years ago
V = d/t
dangina [55]

Answer:

Explanation:

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Showing results for V = d/t a = (V - Vil/t Vaverage = (V+ + V)/2 with constant acceleration d = Vit + 2 at? Vi = (V2 + 2ad)1/2 =VV2 + 2ad A stick figure throws a ball straight up into the air at 5 m/s. g = "-9.81" m/s2 1. How long does it take to reach the top? 2. How long does it take to come back to the level of release? 3. If the hand is 1 m from the ground, how long will it take to hit the ground if the ball is not caught? 4. How high is the ball at the top from the ground? 5. What is the displacement of the ball, if it is caught on return? 6. What is the displacement of the ball to the top from release? 7. What is final velocity when you catch the ball on return to your hand? 8. What is the final velocity as it hits the ground? 9. What is the velocity at the top?

Search instead for V = d/t a = (V - Vil/t Vaverage = (V+ + V)/2 with constant acceleration d = Vit + 2 at? Vi = (V2 + 2ad)1/2 =VV2 + 2ad A stick figure throws a ball straight up into the air at 5 m/s. g = -9.81 m/s2 1. How long does it take to reach the top? 2. How long does it take to come back to the level of release? 3. If the hand is 1 m from the ground, how long will it take to hit the ground if the ball is not caught? 4. How high is the ball at the top from the ground? 5. What is the displacement of the ball, if it is caught on return? 6. What is the displacement of the ball to the top from release? 7. What is final velocity when you catch the ball on return to your hand? 8. What is the final velocity as it hits the ground? 9. What is the velocity at the top?

7 0
3 years ago
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