Answer:
Zn+H2O ------ ZnO + H2 is the correct answer
I think it’ll be option B.
Answer:
![Al(OH)_{3}(s)+3H^{+}(aq.)+3Br^{-}(aq.)\rightarrow Al^{3+}(aq.)+3Br^{-}(aq.)+3H_{2}O(l)](https://tex.z-dn.net/?f=Al%28OH%29_%7B3%7D%28s%29%2B3H%5E%7B%2B%7D%28aq.%29%2B3Br%5E%7B-%7D%28aq.%29%5Crightarrow%20Al%5E%7B3%2B%7D%28aq.%29%2B3Br%5E%7B-%7D%28aq.%29%2B3H_%7B2%7DO%28l%29)
![Al(OH)_{3}(s)+3H^{+}(aq.)\rightarrow Al^{3+}(aq.)+3H_{2}O(l)](https://tex.z-dn.net/?f=Al%28OH%29_%7B3%7D%28s%29%2B3H%5E%7B%2B%7D%28aq.%29%5Crightarrow%20Al%5E%7B3%2B%7D%28aq.%29%2B3H_%7B2%7DO%28l%29)
Explanation:
Aluminium hydroxide (
) is a base and hydrobromic acid (HBr) is a strong acid.
Hence an acid-base reaction occurs between
and HBr
Balanced molecular equation:
![Al(OH)_{3}(s)+3HBr(aq.)\rightarrow AlBr_{3}(aq.)+3H_{2}O(l)](https://tex.z-dn.net/?f=Al%28OH%29_%7B3%7D%28s%29%2B3HBr%28aq.%29%5Crightarrow%20AlBr_%7B3%7D%28aq.%29%2B3H_%7B2%7DO%28l%29)
Balanced total ionic equation:
![Al(OH)_{3}(s)+3H^{+}(aq.)+3Br^{-}(aq.)\rightarrow Al^{3+}(aq.)+3Br^{-}(aq.)+3H_{2}O(l)](https://tex.z-dn.net/?f=Al%28OH%29_%7B3%7D%28s%29%2B3H%5E%7B%2B%7D%28aq.%29%2B3Br%5E%7B-%7D%28aq.%29%5Crightarrow%20Al%5E%7B3%2B%7D%28aq.%29%2B3Br%5E%7B-%7D%28aq.%29%2B3H_%7B2%7DO%28l%29)
Balanced net ionic equation:
![Al(OH)_{3}(s)+3H^{+}(aq.)\rightarrow Al^{3+}(aq.)+3H_{2}O(l)](https://tex.z-dn.net/?f=Al%28OH%29_%7B3%7D%28s%29%2B3H%5E%7B%2B%7D%28aq.%29%5Crightarrow%20Al%5E%7B3%2B%7D%28aq.%29%2B3H_%7B2%7DO%28l%29)
(net ionic equation is written by removing common ions present in both side of total ionic equation)
Answer:
450.0 L.
Explanation:
- We can use the general law of ideal gas: <em>PV = nRT.</em>
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If n and T are constant, and have different values of P and V:
<em>(P₁V₁) = (P₂V₂).</em>
<em></em>
V₁ = 760.0 L, P₁ = 450.0 mm Hg,
V₂ = ??? L, P₂ = 760.0 mm Hg (standard pressure = 1.0 atm = 760 mm Hg).
∴ V₂ = (P₁V₁)/(P₂) = (760.0 L)(450.0 mm Hg)/(760.0 mm Hg) = 450.0 L.
<h3>Heya</h3><h3>Here is your answer</h3><h3>________________</h3><h3></h3><h3>A temperature of 20°C is equivalent to approximately 68 degree Fahrenheit (standard room temperature).</h3><h3></h3><h3>==================</h3><h3></h3><h3>Hope this helped!!!</h3><h3>Happy to help :)</h3>