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2 years ago

14

Everyone needs a certain number of ____________ to meet their daily energy needs.

1 answer:

Ganezh [65]2 years ago

8 0

Answer:

The answer is calories.

The average human being needs 2000 calories for them to be energized.

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Which element has 13 protons and 8 neutrons?

WINSTONCH [101]

Answer:

only thing close I can see would be aluminun

Explanation:

atomic number of 13 and 8 2nd electrons in its shell.

5 0

2 years ago

Read 2 more answers

What’s the answer????

maks197457 [2]

Answer:

Greater

Greater

Explanation:

The amplitude of a wave is the height of the wave or the vertical displacement of the wave motion. We determine a wave amplitude usually by looking at the graph of the wave.

Amplitude is directly proportional to the energy of a wave. The higher the amplitude of a wave, the more its energy.

Frequency is the number of waves that passes a point at a particular instance of time. It is also directly proportional to the energy carried by a wave. The higher the frequency of a wave, the greater its energy.

4 0

2 years ago

Describe why corrosion is a natural process

Sladkaya [172]

<u>Answer :</u>

<u>Answer :because it happens due to moisture and oxygen </u>

6 0

2 years ago

How many Molecules are in 20 grams of CO?

Mademuasel [1]

Answer:

2.74 x 1023 molecules of CO2.

Explanation:

There are 2.74 x 1023 molecules of CO2.

7 0

2 years ago

The percent by mass of bicarbonate (HCO3−) in a certain Alka-Seltzer product is 32.5 percent. Calculate the volume of CO2 genera

nevsk [136]

Answer:

The volume of carbon dioxide gas generated 468 mL.

Explanation:

The percent by mass of bicarbonate in a certain Alka-Seltzer = 32.5%

Mass of tablet = 3.45 g

Mass of bicarbonate = $3.45 g\times \frac{32.5}{100}=1.121 mol$

Moles of bicarbonate ion = $\frac{1.121 g/mol}{61 g/mol}=0.01840 mol$

$HCO_3^{-}(aq)+HCl(aq)\rightarrow H_2O(l)+CO_2(g)+Cl^-(aq)$

According to reaction, 1 mole of bicarbonate ion gives with 1 mole of carbon dioxide gas , then 0.01840 mole of bicarbonate ion will give:

$\frac{1}{1}\times 0.01840 mol=0.01840 mol$ of carbon dioxide gas

Moles of carbon dioxide gas n = 0.01840 mol

Pressure of the carbon dioxide gas = P = 1.00 atm

Temperature of the carbon dioxide gas = T = 37°C = 37+273 K=310 K

Volume of the carbon dioxide gas = V

$PV=nRT$ (ideal gas equation)

$V=\frac{nRT}{P}=\frac{0.01840 mol\times 0.0821 atm L/mol K\times 310 K}{1.00 atm}=0.468 L$

1 L = 1000 mL

0.468 L =0.468 × 1000 mL = 468 mL

The volume of carbon dioxide gas generated 468 mL.

5 0

3 years ago